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3 years ago

If the zeroes of the polynomial x^3-14x^2+37x-60 are alpha,beta,gamma,then find

Mathematics

1 answer:

inessss [21]3 years ago

6 0

Oh oh yes hablo muy poco inglés como para aiufarte

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Heeeeeeeeeeeeeeeelppp asap 35 points on the line

Vlad1618 [11]

Answer:

may be. 2 /5 × x=14

2x/5=14

2x=14×5

2x=70

x=70/2

x=35

5 0

3 years ago

What represents the algebraic expression 3 p + 6 Over 7 p minus 9

MatroZZZ [7]

The answer is the sum of three times a number and six, divided by the difference of seven times a number and nine.

The phrase is(3p+6)/(7p-9)
Let’s describe each factor:
3p is three times a number
7p is seven times a number

3p+6 is the sum of three times a number and six
7p-9 is the difference of seven times the number and nine

The last two factors are divided, so
(3p+6)/(7p-9) is the sum of three times a number and six, divided by the difference of seven times the number and nine.

I hope this helped and have a nice day!

7 0

4 years ago

Svet_ta [14]

Answer: 120/21=40/7

49/19

240/20=12/1

36/14=18/7

63/13=63/13

12/7=12/7

6/6=1/1

Step-by-step explanation:

5 0

3 years ago

5. 2072 Set EQ. NO. 96 An article is sold for Rs. 150 with profit. Had it been sold for Rs 135. there would have been a loss equ

aksik [14]

Answer:

I don't know the answer

3 0

3 years ago

Sketch these four lines y = 2x+1, y =-x, and x = 0 and x = 2. Then use integrals to find the area of the region bounded by these

Yuliya22 [10]

Answer:

Area = 8

Step-by-step explanation:

A skecth is given in the attached file, there are two extra lines used to calculate the area with simple geometry:

We must use a double integral to obtain the area:

$\int\limits^2_0 {\int\limits^b_a \, dy } \, dx$

Where

b stands for y=2x+1

a stands for y=-x

Carring out the integrals we find the area:

$\int\limits^2_0 {(2x+1 - (-x))} \, dx = \int\limits^2_0 {3x+1} \, dx = (3x^{2}/2+x) \left \{ {{2} \atop {0}} \right.\\ A =( 3*2^{2}/2) + 2 =8$

Geometrically we can divide the area bounded by this lines as two triangles and a rectangle from the figure and the intersection of these lines we kno that the three figures have a base of 2. The heigth of the rectangle is 1 and for the triangles we have 4 for the upper triangle and 2 for the lower.

Therefore:

$A = A_{upperT}+ A_{rect}+ A_{lowerT}$

and

$A_{upperT}=2*4/2=4\\A_{rect}=2*1=2\\ A_{lowerT}=2*2/2=2$

Summing the four areas we have:

A=8

Greeting!

3 0

3 years ago