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2 years ago

Which expressions are equivalent to 7x – 14? Check all that apply.

Mathematics

2 answers:

Andrew [12]2 years ago

8 0

Answer:

$\huge\boxed{-(14-7x)}\\\\\huge{\boxed{7(x-2)}}\\\\\huge\boxed{3x-14+4x}$

Step-by-step explanation:

All of the following equations, through the Distributive Property and combining like terms, simplify to 7x - 14.

-(14 - 7x)

Distribute.

(-1)*14 + (-1)*7x

Simplify.

-14 + 7x

Rearrange.

7x - 14

7(x - 2)

Distribute.

(7*x) + (7 * -2)

Simplify.

7x - 14

3x - 14 + 4x

Combine like terms.

7x - 14

Hope it helps :)

makvit [3.9K]2 years ago

5 0

Answer:

Answer is 3x – 14 + 4x

3x – 14 + 4x = 7x - 14

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

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Subtract 8 y^2 − 5 y + 7 from 2 y^2 + 7 y + 1 1 <br><br> The answer is: −6y ^2 +12y+4

lys-0071 [83]

Answer:

$\large\boxed{-6y^2+12y+4}$

Step-by-step explanation:

$(2y^2+7y+11)-(8y^2-5y+7)\\\\=2y^2+7y+11-8y^2-(-5y)-7\\\\=2y^2+7y+11-8y^2+5y-7\qquad\text{combine like terms}\\\\=(2y^2-8y^2)+(7y+5y)+(11-7)\\\\=-6y^2+12y+4$

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4 years ago

What square root is larger that the square root of 17

Ymorist [56]

Answer:

i would have to say the square root of 26 since its 5.099

Step-by-step explanation:

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3 years ago

Mrs. Baker paid $2.50 for 5 pounds of bananas. Write an equation relating to the cost to the number of pounds of bananas. How mu

tensa zangetsu [6.8K]

The equation is 2.50÷5=x
2.50÷5=.50
Mrs. Baker paid $2.50 for 5 pounds of bananas
If x=.50 per banana
Then to get the cost of 8 bananas, you would do 8×.50=$4.00
Mrs. Baker paid $4.00 for 8 pounds of bananas
Each banana costs .50 cents per pound

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4 years ago

Read 2 more answers

Simplify the left side of the equation.

andreev551 [17]

Answer:

Step-by-step explanation:

14 + 10 = 24.

The Question has given hints.

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3 years ago

A rectangular poster is to contain 512 square inches of print. The margins at the top and bottom of the poster are to be 2 inche

goldfiish [28.3K]

Answer:

Poster dimensions:

w = 18 in

h = 36 in

A(min) = 648 in²

Step-by-step explanation:

Printed area for the rectangular poster is:

512 in²

If we call "x" and "y" dimensions of printed area we have:

512 = x*y ⇒ y =512/x

According to problem statment dimensions of the poster will be:

w = x + 2 and h = y + 4

Then area of the poster is:

A(p) = w*h ⇒ A(p) = ( x + 2 ) * ( y + 4 )

A(p) = x*y + 4*x + 2*y + 8

And as y = 512/x we can express A(p) as a function of x

A(x) = x* (512/x) + 4*x + 2*(512/x) + 8

A(x) = 512 +4*x + 1024/x + 8 ⇒ A(x) = 520 +4*x + 1024/x (1)

Taking derivatives on both sides of the equation (1) we get:

A´(x) = 4 - 1024/x²

A´(x) = 0 ⇒ 4 - 1024/x² = 0

4*x² = 1024

x² = 1024/4

x² = 256

x = 16 in and y = 512/16 y = 32 in

The value of A´(16) = 0 since 1024 /256 = 4

And A´´(x) = - [ - 1024(2x)/ x⁴] will be A´´(x) > 0

Then the function has a minimum for x = 16

And dimensions of the poster are:

w = x + 2 w = 18 in

h = y + 4 y = 36 in

A (min) = 36*18

A (min) = 648 in²

6 0

3 years ago