3 years ago

Use an array and partial products to find

1 answer:

3 0

Well done mate you’re correct.

You might be interested in

nlexa [21]

Answer:

you cheater

Step-by-step explanation:

Tring to cheat because you don't feel like doing it. Hopefully you fail so you can learn your lesson

5 0

2 years ago

mojhsa [17]

Ukonczyła 20-ścia 30-dziestych

6 0

3 years ago

Ludmilka [50]

Answer:

B 2/3

Step-by-step explanation:

5 0

3 years ago

Yuliya22 [10]

Answer:

I believe it is an acute angle

6 0

3 years ago

daser333 [38]

Answer:

B. 1/2

Step-by-step explanation:

$\lim_{z \to 0} \frac{g(z)e^{-z}-3}{z^{2}-2z}$

If we plug in 0 for z, we get 0/0. Apply l'Hopital's rule.

$\lim_{z \to 0} \frac{-g(z)e^{-z}+g'(z)e^{-z}}{2z-2}$

Now when we plug in 0 for z, we get:

$\frac{-g(0)e^{0}+g'(0)e^{0}}{2(0)-2}\\\frac{-g(0)+g'(0)}{-2}\\\frac{-3+2}{-2}\\\frac{1}{2}$

4 0

3 years ago