Question

A baseball pitcher has made 53 pitches in the first four innings of a baseball game and plans to pitch 3 mote innings. The manager of the team has committed to allowing his pitcher to throw, at most, pitches during the game. Write an inequality to find the average number of pitches the pitcher can throw over the next three innings Solve the inequality from Part 1. What is the maximum number of pitches the pitcher can make in cach of the next 3 innings ? Graph your solution from Part 2 on a number line and explain what your solution means. If the pitcher threw just 6 pitches in the fifth inning, what is the greatest number of pitches the pitcher can throw per inning he wishes to pitch nine innings? Write and solve an inequality to answer this part.

Answer 1

Answer:

at most 17 pitches per inning

Step-by-step explanation:

It is given that a baseball pitcher makes 53 pitches in the first 4 innings of a game and plans to pitch in the next 3 innings.

We need to write and solve an inequality to find the possible average pitches per inning the pitcher made in the next 3 innings if the pitcher is assigned a maximum of 105 pitches.

From part (a) we know  3 p + 53 3p+53 represents the total number of pitches made if the pitcher makes an average of  p pitches per inning in the next 3 innings.

If the pitcher can make at most 105 pitches, then:

3 p + 53 ≤ 105 3p+53≤105 ​  

To solve the inequality, first subtract 53 on both sides of the inequality to isolate the variable term:

3 p + 53 − 53 ≤ 105 − 53 3 p ≤ 53      

3p+53≤105 $p\leq 17\frac{1}{3}$

at most 17 pitches per inning

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(Hope this helps can I pls have brainlist (crown)☺️)