Answer:
y+11=-2/3(x-6)
Step-by-step explanation:
To find the parallel line, we would just plug in the numbers in the point-slope form from what we're given. We have y=-2/3x+12 and (6,-11).
Point-slope form:
y-y1=m(x-x1) → y+11=-2/3(x-6)
m represents the slope, which is -2/3 in this situation.
y1 represents the y coordinate, which is -11 in this situation. However, when we plug in negative numbers in a point-slope form, we would do the opposite of the negative number, which is to make it a positive in point-slope form.
x1 represents the x coordinate, which is 6 in this situation.
Quadrant IV
at quadrant IV, sinA is negative value while cosA is positive value
Answer:
IJ = 34
Step-by-step explanation:
Since HK = JK, then IK is a perpendicular bisector and Δ is isosceles, then
IJ = HI , that is
2s = s + 17 ( subtract s from both sides )
s = 17
Then
IJ = 2s = 2 × 17 = 34
Answer:
Step-by-step explanation:
28/40 ×100 =70 PERCENT
