Answer:
at 2/3 seconds
Step-by-step explanation:
S1(t) = t³ + 2
Average speed, dS1/dt = 3t²
S2(t) = t²
Average speed, dS2/dt = 2t
The distance between the objects is
dS1/dt - dS2/dt
= 3t² - 2t
The time the distance between the two object is at minimum is when the distance is 0
That is, when
3t² - 2t = 0
t(3t - 2) = 0
t = 0 or 3t - 2 = 0
t = 0 or t = 2/3
9514 1404 393
Answer:
- boat: 48 km/h
- current: 14 km/h
Step-by-step explanation:
The upstream speed is ...
u = (204 km)/(6 h) = 34 km/h
The downstream speed is ...
d = (372 km)/(6 h) = 62 km/h
The speed of the boat in still water is the average of these values:
b = (34 kph +62 kph)/2 = 48 kph
The speed of the water is the difference between the boat's speed and the speed made good:
w = 48 -34 = 14 . . . km/h
The rate of the boat in still water is 48 km/h. The rate of the current is 14 km/h.
If the problem is supposed to read (4^33*8^37)/(4^15*8^21), then...
(4^33*8^37)/(4^15*8^21) = (4^33/4^15)*(8^37/8^21)
(4^33*8^37)/(4^15*8^21) = 4^(33-15)*8^(37-21)
(4^33*8^37)/(4^15*8^21) = 4^18*8^16
Answer: Choice A) 4^18*8^16
Answer:
3x - 14
Step-by-step explanation:
Perimeter = 2(length+width)
= 2[(½X-7) + (x)]
= 2[½x + x - 7]
= 2[1.5x - 7]
= 3x - 14
.01 + .01 = .02
.01 - .01 = .00
