We have that
<span>Log3 a/3
</span>Rewrite log3(a/3) using the change of base <span>formula
we know that
</span>The change of base rule can be used if a and b are greater than 0 and not equal to 1, and x is greater than 0<span>.
</span>so
loga(x)=<span>logb(x)/<span>logb<span>(a)
</span></span></span>Substitute in values for the variables in the change of base <span>formula
</span>
in this problem
b=10
a=3
x=a/3
log3(a/3)=[log (a/3)]/[log (3)]
the answer is
[log (a/3)]/[log (3)]
I got 4 but i’m not 100% correct
Hello,
x^3+7x^2+10x-6=x^3+3x^2+4x^2+12x-2x-6
=x²(x+3)+4x(x+3)-2(x+3)
=(x+3)(x²+4x-2)
=(x+3)(x+2-√7)(x+2+√7)
zeroes={-3,-2+√7,-2-√7}
This is referred to as a Chemical Bond.
Answer:
s
Step-by-step explanation:
