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Lelechka [254]
3 years ago
11

Points P and Q belong to segment AB. If AB = a, AP = 2PQ = 2QB, find the distance: a between point A and the midpoint of the seg

ment QB
Mathematics
1 answer:
PIT_PIT [208]3 years ago
8 0

Since PQ = QB, PB = 2PQ = AP. Thus P is the midpoint of AB, and Q is the midpoint of PB. Then the midpoint (X) of QB is AP + PQ + QX = 1/2 + 1/4 + 1/8 times the length of AB from A.

The distance from A to the midpoint of QB is (7/8)a.

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A standard cube has 6 possible outcomes. But since we want to find P(4+ or odd), the outcomes become more narrow.
So:
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But we want to find 4+
So:
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We also want to find all odd possibilities.
So:
odd = 1, 3, 5

As you can see, there is a 5 in both the 4+ and the odd numbers so 5 will only be counted once.
P(4+ or odd) = 1, 3, 4, 5, 6

So the probability of having an outcome that is P(4+ or odd) is:
5/6 or 0.8333 or 83.33%

Hope I helped!
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Step-by-step explanation:

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3 years ago
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