All categories

2 years ago

Who is wardy joubert? does he have a large one?

SAT

2 answers:

Elina [12.6K]2 years ago

8 0

yes he has a very large one

bixtya [17]2 years ago

4 0

Answer:

WARDY JOUBERT ||| was known for his famous picture taken in 2010. The picture was taken and had a very, very, very large third leg.

Explanation:

He died by s triyng to feed his starving family. THe picture was meant to raise money for his family.

You might be interested in

In 2009, regulations for credit cards were changed bya. agreements between bankers and borrowersb. the credit cardholders' bill

aleksklad [387]

I think you have your question confused

6 0

3 years ago

The mantle makes up ____ % of the Earth

iren2701 [21]

Answer: 84%

Explanation:

7 0

3 years ago

A point charge q1 = -4. 00 nc is at the point x = 0. 60 m, y = 0. 80 m , and a second point charge q2 = +6. 00 nc is at the poin

Alekssandra [29.7K]

The net electric field is the vector sum of the components of the electric

field produced by the two charges.

The values of the magnitude and direction of the net electric field at the origin (approximate values) are;

131.6 N/C

12.6 ° above the negative x–axis

<h3>How are the net electric field magnitude and direction calculated?</h3>

The possible questions based on a similar question posted online are;

(a) The net electric field at the origin.

The electric field due to charge q₁ is given as follows;

$\vec E_{1x} = \mathbf{ \dfrac{1}{4 \cdot \pi \cdot \epsilon_0} \cdot \dfrac{q_1}{\vec{r}^2_2}}$

Which gives;

$\vec{E}_{1x} =\mathbf{ \dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(-4 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2}} \cdot cos\left(arctan\left(\dfrac{0.8}{0.6} \right) \right) =-21.6 \, N/C$

$\vec{E}_{1y} = \mathbf{\dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(-4 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2}} \cdot sin\left(arctan\left(\dfrac{0.8}{0.6} \right) \right) = 28.8 \, N/C$

Which gives;

$\vec{E}_1 = \mathbf{21.6 \, N/C \cdot \hat x + 28.8 \, N/C \hat y}$

$\vec{E}_{2x} = \dfrac{\left(9 \times 10^9 \, N \cdot m/C^2 \right) \cdot \left(6.00 \, nC \times \dfrac{10^{-9}C}{1 \, nC} \right)}{\left(1 \, m \right)^2} = 150 \, N/C$

Therefore;

$\vec {E} = \left[ 21.6 \, N/C - 150 \, N/C \right] \left( \hat x \right) + \left(28.8 \, N/C \right) \left( \hat y \right)$

$\vec {E} = \mathbf{\left( -128.4 \, N/C \right) \left( \hat x \right) + \left(28.8 \, N/C \right) \left( \hat y \right)}$

The magnitude of the net electric field is therefore;

E = $\sqrt{(-128.4^2 + 28.8^2)}$ ≈ 131.6

The magnitude of the net electric field at the origin is E ≈<u> 131.6 N/C</u>

(b) The direction of the net electric field at the origin.

$The \ direction \ is \ arctan \left(\dfrac{28.8}{-128.4} \right) \approx \underline{ 12.6^{\circ}} \ above \ the \ negative \ x-axis$

Learn more about electric field strength here:

brainly.com/question/14743939

brainly.com/question/3591946

3 0

2 years ago

PLEASEEE HELPPP ASAP I WILL GIVE BRAINLSIT There is pollution that has spilled into a lake. Explain why the birds who live on th

BlackZzzverrR [31]

Answer:

The birds are more likely to survive than the fish because the fish actually live in the lake and get resources from there. If the lake gets polluted, the water, oxygen, and food will get worse and the fish will slowly start to die. But the birds can just look for their resources somewhere else.

3 0

2 years ago

Which of the following is not a psychological adaptation

seropon [69]

What are the choices?

5 0

2 years ago

Read 2 more answers