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3 years ago

Help with khan academy

Mathematics

2 answers:

Phantasy [73]3 years ago

8 0

C can be seen as it is located on the point 1.
B is the value which is greater than zero.
A is the value which is less than zero.
B is -2/7.
A is -4/7.
C is 0.

VladimirAG [237]3 years ago

4 0

I’ve attached my work, hope it helps, just flip a and b

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Find an equation of the sphere with center (2, −10, 3) and radius 5. $$25=(x−2)2+(y−(−10))2+(z−3)2 use an equation to describe i

lana66690 [7]

In the $x,y$ plane, we have $z=0$ everywhere. So in the equation of the sphere, we have

$25=(x-2)^2+(y+10)^2+(-3)^2\implies(x-2)^2+(y+10)^2=16=4^2$

which is a circle centered at (2, -10, 0) of radius 4.

In the $x,z$ plane, we have $y=0$ , which gives

$25=(x-2)^2+10^2+(z-3)^2\implies(x-2)^2+(z-3)^2=-75$

But any squared real quantity is positive, so there is no intersection between the sphere and this plane.

In the $y,z$ plane, $x=0$ , so

$25=(-2)^2+(y+10)^2+(z-3)^2\implies(y+10)^2+(z-3)^2=21=(\sqrt{21})^2$

which is a circle centered at (0, -10, 3) of radius $\sqrt{21}$ .

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Dima020 [189]

Answer:

Sure this is a question from probability

Possible 2^n can be use

2^35 =3.432597387 × 10^10

Step-by-step explanation:

I'm not sure

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jeka94

Answer:

Triangle CED

Step-by-step explanation:

C and M need to both be at the same places in their respective equations.

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