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Aleks [24]
3 years ago
10

The triangle below models a section of the supports you might see in a construction crane.

Mathematics
1 answer:
IgorLugansk [536]3 years ago
3 0

Exactly what was your answer for a

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Outline the process for inscribing a regular hexagon in a circle. Perform the construction in GeoGebra
mr_godi [17]

The following are the general steps to draw a hexagon inscribed in a circle:

First draw a circle with center A through B:

Then the intersection points will be vertex C and vertex D of the hexagon. Doing this for each vertex (from left to right) we will get the following:

4 0
1 year ago
8<br> p varies directly as the square root of q.<br> p = 8 when q = 25.<br> Find p when q = 100.
Lostsunrise [7]

Answer:

16

Step-by-step explanation:

p=k√q

8=k√25

8=k5

k=8/5

p when q=100

p=8/5*√100

p=8/5*10

p=16

4 0
3 years ago
The number 3 help now please
PSYCHO15rus [73]
-6, all of them are the absolute value of 6 or just 6, -6 isn't equivalent to 6. 
7 0
3 years ago
Read 2 more answers
Factor by grouping : xy + 6y - 2x - 12 (if you don't know the answer don't comment)
alexira [117]
<h3> Hey There today we will solve your problem</h3>

First we will factor out y from xy+6y which gives us y(x+6)

Next we will factor out -2 from -2x-12 which gives us -2(x+6)

This gives us the equation

y(x+6)-2(x+6)

then factor out the common term  x+6<em> and we get</em>

<em />\left(x+6\right)\left(y-2\right)

6 0
3 years ago
Need urgent help in mathematics!! Will mark brainliest!!!!
sesenic [268]

Hey there!!

How do we solve this problem :

We will use the combinations formula to solve this :

c ( n , r ) where n = 11 and r = 2

c ( n , r ) =  n ! / r ! ( n - r ) !

... 11 ! / 2 ! ( 11 - 2 ) !

... 11! / 2! × 9!

... 11! / 2 × 9!

... 11×10×9×8×7×6×5×4×3×2 / 2×9×8×7×6×5×4×3×2

... 11×10 / 2

... 11 × 5

... 55 combinations.

Hence, the required answer = 55 , option ( d )

Hope my answer helps!

8 0
3 years ago
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