I don't know specifically what the sum and product of an equation is but
factor using quadratic formula
if you have an equation in ax^2+bx+c=0 then you can solve for x using
or
so input
a=1
b=7
c=2
=aprox -0.2984378812836
=aprox -6.7015621187165
Answer:
14hrs
Step-by-step explanation:
v = speed in still water
t = downstream trip time
d = distance = 182 miles; same distance both downstream and upstream
t + 12 = upstream return trip time
u = current flow = 3 mph
Downstream: d = (v + u)t; Upstream: d = (v - u)(t + 12)
(v - 3)(t + 12) = 182 (equation 1)
(v + 3)t = 182 (equation 2)
Subtract equation 2 from equation 1 to get t:
(vt + 12v -3t -36) - (vt + 3t) = 0
12v - 6t - 36 = 0
t = 2v - 6
Substitute this result for t into equation 2 and solve for v:
(v + 3)(2v - 6) = 182
2v^2 - 6v + 6v - 18 = 182
v^2 = 100
v = 10 mph
t = 2v - 6 = [2(10) - 6] hrs = 14 hrs
The answer is No it is not
Solve your equation step-by-step.
2(x−3)−17=13−3(x+2)
Simplify both sides of the equation.
2(x−3)−17=13−3(x+2)
Simplify
2x−23=−3x+7
Add 3x to both sides.
2x−23+3x=−3x+7+3x
5x−23=7
Add 23 to both sides.
5x−23+23=7+23
5x=30
Divide both sides by 5.
5x/5 = 30/5
x=6
Use substitution and substitute y into the other equation. One of the equations already gives you y in terms of x, so use that and substitute it into the other equation. y = 3x - 4
Plug into the other equation: -3y = -9x + 12
-3(3x-4) = -9x + 12
-9x + 12 = -9x + 12
This is an identity. So that means that any value of x makes this equation true. So B.
