4/3th a 100th per distance of both.
Perpendicular bisectors of the sides of triangles are used to draw the circle that passes through corners of the triangle.
Gien that perpendicular bisectors of a triangle are concurrent.
So that means common point will be A) Circumcenter.
Do I have to do all of them?
Since CB || ED and CB = ED,
by the alternate interior angles theorem,
mE = mC, and mD = mB.
with CB = ED, we can conclude that CBF = EDF, by SAS congruent theorem.
Answer:
Y = 0x + b
2 = 0 + b, b = 2
Y = 2
Step-by-step explanation:
