Answer:
Option a. int max = aList.get(0); for (int count = 1; count < aList.size(); count++) { if (aList.get(count) > max) { max = aList.get(count); } }
is the correct code snippet.
Explanation:
Following is given the explanation for the code snippet to find largest value in an integer array list aList.
- From the array list aList, very first element having index 0 will be stored in the variable max (having data type int).
- By using for starting from count =1 to count = size of array (aList), we will compare each element of the array with first element of the array.
- If any of the checked element get greater from the first element, it gets replaced in the variable max and the count is increased by 1 so that the next element may be checked.
- When the loop will end, the variable max will have the greatest value from the array aList.
i hope it will help you!
Answer:
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Explanation:
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I saw this question while reviewing the notes in class
Answer:
a) Internal Forwarding is not used = 26 clock cycles
b)Internal Forwarding is used= 22 clock cycles
The method calcPyramidVolume is an illustration of the java methods; where the methods are executed when called or evoked
<h3>The main program</h3>
The program written in Java, where comments are used to explain each action is as follows:
//This defines the calcPyramidVolume method
public static double calcPyramidVolume(double baseLength,double baseWidth, double pyramidHeight) {
//This calculates the volume of the pyramid
double PyramidVolume = calcBaseArea(baseLength,baseWidth) * pyramidHeight;
//This returns the volume of the pyramid
return PyramidVolume;
}
Read more about java methods at:
brainly.com/question/19271625
