Hi!
Our computers will have system software and application software. Application software would be something like a game or just any general purpose app you've downloaded.
Hopefully, this helps! =)
Answer:
public class Triangle
{
public static void main( String[] args )
{
show( 5 );
}
public static void show( int n )
{
int i,j,k;
for (i = 0; i < n - 1; i++ )
{
for (j = 0; j < i; j++ )
{
System.out.print( " " );
}
for (k = n - i; k > 0; k-- )
{
System.out.print( "* " );
}
System.out.println();
}
for (i = 0; i < n; i++ )
{
for (j = n - i; j > 1; j-- )
{
System.out.print( " " );
}
for (k = 0; k < i + 1; k++ )
{
System.out.print( "* " );
}
System.out.println();
}
Answer:
The output is "A"
Explanation:
public class Solution {
public static void main(String args[]) {
mystery(7);
}
public static void mystery(int a) { System.out.println("A"); }
public static void mystery(double a) { System.out.println("B"); }
public static void mystery(int a, double b) { System.out.println("C"); }
public static void mystery(double a, int b) { System.out.println("D"); }
}
In the code above; mystery is defined in four different ways called method overloading. Method overloading is when same method is defined with different parameters.
In the first case; mystery will be called if the argument is int.
In the second case; mystery will be called if the argument is double.
In the third case; mystery will be called if the arguments are int and double.
In the fourth case; mystery will be called if the arguments are double and int.
When mystery(7) is called; the mystery method requiring only int will be called and the output is "A".
I think the answer to this would be true
