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3 years ago

What is the slope for the graph?

Mathematics

1 answer:

olya-2409 [2.1K]3 years ago

4 0

Answer:

acute

Step-by-step explanation:

it like a angle and acute is a small

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If you were dividing X6 + 4x3 + 2, how many O's would you

skad [1K]

Answer:

how many O's u would use would be 4

Step-by-step explanation:

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3 years ago

If you were asked to find the 87th term in a sequence, which formula would you want to be given?

koban [17]

To determine the nth term of sequence, first we need to know what type of sequence is it. It can be an arithmetic sequence or a geometric sequence. For an arithmetic sequence, the nth can be determined by the formula,

an = a1 + (n-1)d

For a geometric sequence,

an = a1r^n-1

Hope this answers the question.

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3 years ago

drives 312 hours on the highway and 112 hours in the city. What is Fiona's average speed for the entire trip to her grandmother'

melomori [17]

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3 years ago

Write the slope-intercept form of the equation of the line described

OLga [1]

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8 0

4 years ago

The mean of a population is 74 and the standard deviation is 16. The shape of the population is unknown. Determine the probabili

bulgar [2K]

Answer:

$P(X > 75)= 0.35402$

$P(72 < X < 75 ) = 0.2529$

$P( X < 74.7) = 0.74041$

Step-by-step explanation:

From the question we are told that

The population mean is $\mu = 74$

The population standard deviation is $\sigma = 16$

Considering question a

The sample size is n = 36

Generally the standard error of mean is mathematically represented as

$\sigma_{x} = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_{x} = \frac{16}{\sqrt{36} }$

=> $\sigma_{x} = 2.67$

Generally the probability that a random sample of size 36 yielding a sample mean of 75 or more is mathematically represented as

$P(X > 75) = P( \frac{X - \mu }{ \sigma_{x}} > \frac{75 - 74}{ 2.67 } )$

$\frac{X -\mu}{\sigma } = Z (The \ standardized \ value\ of \ X )$

$P(X > 75) = P(Z > 0.3745 )$

From the z table the area under the normal curve representing 0.3745 to the right is

$P(Z > 0.3745 ) = 0.35402$

=> $P(X > 75)= 0.35402$

Considering question b

The sample size is n = 104

Generally the standard error of mean is mathematically represented as

$\sigma_{x} = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_{x} = \frac{16}{\sqrt{104} }$

=> $\sigma_{x} = 1.5689$

Generally the probability that a random sample of size 104 yielding a sample mean between 72 and 75 is mathematically represented as

$P(72 < X < 75 ) = P(\frac{72 - 74 }{1.5689} < \frac{X - \mu }{\sigma_{x}} < \frac{75 - 74 }{1.5689} )$

=> $P(72 < X < 75 ) = P(-1.275 < Z < 0.375 )$

=> $P(72 < X < 75 ) = P(Z < 0.375 ) - P(Z < -1.275)$

From the z table the area under the normal curve representing -1.275 to to the left is

$P(Z < -1.275) =0.10115$

=> $P(72 < X < 75 ) = 0.35402 - 0.10115$

=> $P(72 < X < 75 ) = 0.2529$

Considering question c

The sample size is n = 217

Generally the standard error of mean is mathematically represented as

$\sigma_{x} = \frac{\sigma }{\sqrt{n} }$

=> $\sigma_{x} = \frac{16}{\sqrt{217} }$

=> $\sigma_{x} = 1.086$

Generally the probability that a random sample of size 217 yielding a sample mean of less than 74.7 is mathematically represented as

$P( X < 74.7) = P(\frac{X - \mu }{\sigma_x} < \frac{ 74.7 - 74 }{ 1.086 })$

=> $P( X < 74.7) = P(Z < 0.6446 )$

From the z table the area under the normal curve representing 0.6446 to to the left is

$P(Z < 0.6446 ) = 0.74041$

=> $P( X < 74.7) = 0.74041$

8 0

3 years ago