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Reil [10]
3 years ago
9

I need all the answers

Mathematics
1 answer:
mafiozo [28]3 years ago
4 0

Answer:<em> 2) 1/5 divided by 3= 0.066666 <- repeating 6.</em>

<em>3) 2 divided by 1/8= 0.25</em>

<em>5) 5 divided by 1/4= 1.25</em>

<em>6) 1/2 divided by 2= 0.25</em>

<em>7) 1/4 divided by 6= 0.01466666</em>

<em>Those are all the answers! You could also use an online calculator to check if they are correct. I hope this will help you pass. May I please get Brainliest, thanks and have a g'dday</em>

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A 100-foot rope from the top of a tree house to the ground forms a 45∘ angle of elevation from the ground. How high is the top o
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Answer:

The height of tree house is 70.71 feet

Step-by-step explanation:

We are given that A 100-foot rope from the top of a tree house to the ground forms a 45∘ angle of elevation from the ground

Refer the attached figure

Length of rope AC = Hypotenuse =100 feet

The top of a tree house to the ground forms a 45∘ angle of elevation from the ground =\angle ACB = 45^{\circ}

We are supposed to find the height of tree house i.e.AB = Perpendicular

So, Using trigonometric ratio

Sin \theta = \frac{perpendicular}{Hypotenuse}\\Sin 45= \frac{AB}{AC}\\\frac{1}{\sqrt{2}}=\frac{AB}{100}\\100 \times \frac{1}{\sqrt{2}}=AB\\70.71=AB

Hence The height of tree house is 70.71 feet

8 0
3 years ago
For a language test with normally distriuted scores, the mean was 70 and the standard deviation was 10. Approximately what perce
Alborosie

Answer: 84.13%

Step-by-step explanation:

Given : The scores in a a language test with normally distributed.

Mean : \mu=70

Standard deviation: \sigma= 10

Let x be the random variable that represents the scores of students.

Formula for z-score: z=\dfrac{x-\mu}{\sigma}

For x= 60 , we have

z=\dfrac{60-70}{10}=-1

The probability f test takers scored a 60 or above :-

P(x\geq60)=P(\geq-1)=1-P(z

Hence, the percentage of test takers scored a 60 or above = 84.13%

6 0
4 years ago
What is the question of this i need it fast and nice plz 2+(c+0)=
yKpoI14uk [10]

Answer:

C02

Step-by-step explanation:

Carbon Dioxide

Hope this helps!

3 0
3 years ago
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