Two shapes.. a circle and a rectangle. The width of the rectangle serves as the diameter of the circle.
Length = 140 m ; Width = 68 m
Circumference of a circle = 2 π r
circumference of a cirlce = 2 * 3.14 * (68m/2) = 2 * 3.14 * 34 m = 213.52
length = 2 * 140 m = 280 m
perimeter of the oval = 213.52 m + 280 m = 493.52 m
Answer:
698765
Step-by-step explanation:fsczsfwdsczssd
Answer:
60 ways
Step-by-step explanation:
Given that an automobile dealer has several options available for each of three different packages of a particular model car: a choice of two styles of seats in three different colors, a choice of four different radios, and five different exteriors.
No of exteriors = 5
No of radios = 4
Number of styles of colours = 3
Thus he can select exterior any one of the five or in 5 ways
Similarly he can select radio in 4 ways and
Number of styles of colours in 3 ways
Choices of automobile a customer has
= product of these three
=
Answer:
The maximum value of P is 32
Step-by-step explanation:
we have following constraints
----> constraint A
----> constraint B
----> constraint C
----> constraint D
Solve the feasible region by graphing
using a graphing tool
The vertices of the feasible region are
(0,2),(0,8),(8,0),(2,0)
see the attached figure
To find out the maximum value of the objective function P, substitute the value of x and the value of y of each vertex of the feasible region in the objective function P and then compare the results
we have
so
For (0,2) --->
For (0,8) --->
For (8,0) --->
For (2,0) --->
therefore
The maximum value of P is 32