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Lelu [443]
2 years ago
6

State one technique for overcoming external fragmentation in dynamic partitioning. Why is this technique of overcoming external

fragmentation considered inefficient
Computers and Technology
1 answer:
prisoha [69]2 years ago
4 0

Compaction often gives solutions to the issues regarding external fragmentation.

One technique for overcoming external fragmentation in dynamic partitioning is

Compaction.

The reason why this technique of overcoming external fragmentation may be inefficient is because:

  • External fragmentation may need a lot of compaction and it is an expensive operation.

  • The use of contiguous allocation is often hard to fit processes into memory and also it is so difficult to grow or shrink the amount of memory allocated to a process.

  • Compaction only takes place when relocation is dynamic, and this also is expensive.

Compaction often shuffle memory notes or contents and then put or pile them up all in free memory and in one large block.

External fragmentation takes place when free memory is removed into small blocks.

Learn more from

brainly.com/question/23636593

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Create a Racket procedure compute_pos that reads numbers from the keyboard until 0 is read, count how many positive numbers are
Artyom0805 [142]

Answer:

import java.util.Scanner;

public class Solution {

   public static void main(String args[]) {

       compute_pos();

     }

     

     public static void compute_pos(){

     Scanner scan = new Scanner(System.in);

     int sum = 0;

     int counter = 0;

     // Prompt the user to enter an input

     System.out.println("Enter your value");

     // user input is assign to the variable value

     int value = scan.nextInt();

     

     while(value != 0){

         if (value > 0){

             sum += value;

             counter++;

         }

         System.out.println("Enter your value");

         value = scan.nextInt();

     }

     // Display the value of sum to the user

     System.out.println("The sum of the positive number is: " + sum);

     // Display the value of counter to the user

     System.out.println("The number of positive number is: " + counter);

   }

}

Explanation:

The first line import the Scanner class which allow the program to read input from the user. The class Solution is then defined. Then the main method which signify the beginning of execution in the program is defined. A method is called inside the main method.

The method compute_pos is defined. Inside the compute_pos method, a scanner object scan is declared to accept input from the user via the keyboard.

The variable sum and counter is declared and assigned to 0.

A prompt is displayed to the user to input a value. The user input is accepted and stored in the variable value.

Then a while loop is use to check the user input if it is not equal to zero. If it is equal to zero, the loop will end. Inside the loop, we first check to see if the user input is greater than 0, if it is, we add it to the variable sum and increase our counter by 1. At the end of the loop, a prompt is again display to accept input from the user.

Outside the loop, we display the sum and counter to the user.

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4 years ago
Rest or take a break every __ minutes when typing. Please help!
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Maybe like 3-5 I think im right
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defon
Answer:
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Explanation:
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Answer:

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