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sergejj [24]
2 years ago
5

if you have 80 feet of fencing and want to enclose a rectangular area up against a long, straight wall, what is the largest area

you can enclose
Mathematics
1 answer:
Len [333]2 years ago
4 0

Answer:

300 ft^2

Step-by-step explanation:

Multiply 30 by 10

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Pls need help 100 points and crown if right!!!
nekit [7.7K]

Answer:

\sf  2\dfrac{1}{4}\ cups \ of \ sugar

Explanation:

Let the full batch be x

Here given:

3/4 cup of sugar required to make 1/3 batch of cookies

Build equation:

\sf \rightarrow \dfrac{1}{3}x  = \dfrac{3}{4} \ cup \ of \ sugar

Solve:

\sf \rightarrow x  = \dfrac{3(3)}{1(4)}

\sf \rightarrow x  = \dfrac{9}{4}

\rightarrow \sf  x = 2\dfrac{1}{4}

5 0
1 year ago
Read 2 more answers
Plz i need help and plz explain
Montano1993 [528]

\frac{ {x}^{2}  - 7x + 12}{ {x}^{2} - x - 12 }  \\  =  \frac{ {x}^{2} - 4x - 3x + 12 }{ {x}^{2} - 4x + 3x - 12 }  \\  =  \frac{x(x - 4) - 3(x - 4)}{x(x - 4) + 3(x - 4)}  \\  =  \frac{(x - 3)(x - 4)}{(x + 3)(x - 4)}  \\  =  \frac{x - 3}{x + 3}

x² - x - 12 ≠ 0

x² - 4x + 3x - 12 ≠ 0

x (x - 4) + 3 (x - 4) ≠ 0

(x + 3)(x - 4) ≠ 0

x ≠ -3 or x ≠ 4

(B)

3 0
3 years ago
training for a cycle race in the first week if I was 195 miles in the second we can manage is 243 Miles what is the percentage i
Ivahew [28]

Answer:

24.61%

Step-by-step explanation:

The distance covered in first week = 195 miles

The distance covered in the second week = 243 miles

We need to find the percentage increase in distance​. It can be calculated as follows :

\%=\dfrac{243-195}{195}\times 100\\\\=24.61\%

So, the increase in distance is equal to 24.61%.

4 0
3 years ago
A stack of 30 science flashcards includes a review card for each of the following: 10 insects, 8 trees, 8 flowers, and 4 birds.
coldgirl [10]
All you have to do is make the fraction of it which is 4/30. Then simplify to 2/15 which is your answer.
4 0
2 years ago
Solid A has a volume of
jonny [76]

Answer: 512 times

Step-by-step explanation:

$$Volume of Solid $A=5632 \mathrm{~cm}^{3}$ \\Volume of Solid $B=11 \mathrm{~cm}^{3}$.\\Divide volume of Solid $A$ by volume of Solid $B$.\\Volume of Solid A\\Volume of Solid $B$\\

\frac{5632 \mathrm{~cm}^{3}}{11 \mathrm{~cm}^{3}}=512\\\\$$\text{Therefore, Solid $A$ is 512 times larger thm Solid B}

7 0
2 years ago
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