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sergejj [24]
2 years ago
5

if you have 80 feet of fencing and want to enclose a rectangular area up against a long, straight wall, what is the largest area

you can enclose
Mathematics
1 answer:
Len [333]2 years ago
4 0

Answer:

300 ft^2

Step-by-step explanation:

Multiply 30 by 10

You might be interested in
What’s the answer does anyone know?
Alexus [3.1K]

56.57

Explanation:
In the process,
Diameter= 18,
Radius(r)=
18
2

∴
Radius= 9
Now,
Circumference (Perimeter) = ?
According to the formula,
Perimeter= 2
×
22
7
×
r

Taking the equation,
Perimeter= 2
×
22
7
×
r

2
×
22
7
×
9

396
7

56.57142857

56.57

Let's hope this helps you:)
8 0
3 years ago
Read 2 more answers
Solve this for fun! I already solved it, so you can give a simple answer.
Ivanshal [37]

is this 8th grade is it is it

4 0
3 years ago
Read 2 more answers
I️ have to use 15 as Y
statuscvo [17]
-1/5of 15 =-3 then add 3 2/5th which is 17/2 so -3+17/2 = 11/2=5 1/2
7 0
3 years ago
Divide -3x^3-2x^2-x-2 by x-2
Rasek [7]

Let's do this by Briot-Ruffini


First: Find the monomial root


x - 2 = 0

x = 2


Second: Allign this root with all the other coeficients from equation

Equation = -3x³ - 2x² - x - 2

Coeficients = -3, -2, -1, -2

2 | -3 -2 -1 -2


Copy the first coeficient


2 | -3 -2 -1 -2

-3


Multiply him by the root and sum with the next coeficient


2.(-3) = -6

-6 + (-2) = -8


2 | -3 -2 -1 -2

-3 -8


Do the same


2.(-8) = -16

-16 + (-1) = -17


2 | -3 -2 -1 -2

-3 -8 -17


The same,


2.(-17) = -34

-34 + (-2) = -36


2 | -3 -2 -1 -2

-3 -8 -17 -36


Now you just need to put the "x" after all these numbers with one exponent less, see


2 | -3x³ - 2x² - 1x - 2

-3x² - 8x - 17 -36


You may be asking what exponent -36 should be, and I say:


None or the monomial. He's like the rest of this division, so you can say:


(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 with rest -36 or you can say:

(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 - 36/(x - 2)


Just divide the rest by the monomial.

5 0
3 years ago
An oil tank has to be drained for maintenance. The tank is shaped like a cylinder that is 5 ft long with a diameter of 1.8 ft .
dangina [55]
\bf \textit{volume of a cylinder}\\\\
V=\pi r^2 h\qquad 
\begin{cases}
r=radius=\frac{diameter}{2}\\
h=height\\
----------\\
diameter=1.8\\
r=\frac{1.8}{2}=0.9\\
h=5
\end{cases}\implies V=\pi \cdot 0.9^2\cdot 5\\\\
-------------------------------\\\\
\textit{is draining at }\boxed{2.1}\ \frac{ft^3}{min}\textit{ , it has a total of }\boxed{\pi \cdot 0.9^2\cdot 5} \ ft^3
\\\\\\
\textit{it'll take }\cfrac{\pi \cdot 0.9^2\cdot 5}{2.1}\ minutes
3 0
3 years ago
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