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2 years ago

9

A moving company charges a flat rate of $85 plus and additional $0.17 per mile driven. How far must the company drive to earn $1

00

1 answer:

Semenov [28]2 years ago

5 0

Answer:

they would have to drive 89 miles to get $100

Step-by-step explanation:

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If tan A = 4/3 and sin B = 45/53 and angles A and B are in Quadrant I, find the value of tan(A+B)

lbvjy [14]

Answer:

First, find tan A and tan B.

cosA=35 --> sin2A=1−925=1625 --> cosA=±45

cosA=45 because A is in Quadrant I

tanA=sinAcosA=(45)(53)=43.

sinB=513 --> cos2B=1−25169=144169 --> sinB=±1213.

sinB=1213 because B is in Quadrant I

tanB=sinBcosB=(513)(1312)=512

Apply the trig identity:

tan(A−B)=tanA−tanB1−tanA.tanB

tanA−tanB=43−512=1112

(1−tanA.tanB)=1−2036=1636=49

tan(A−B)=(1112)(94)=3316

kamina op bolte

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3 0

2 years ago

Is the leg on the bottom the same size as the one on the right?

mash [69]

Answer: The leg on the bottom is small than the leg on the right.

Step-by-step explanation: Right bro.

4 0

2 years ago

If a → b is true, then ~a → b is also true.

Rasek [7]

Answer:

False

Step-by-step explanation:

To determine whether the statemaent "If $a\Rightarrow b$ is true, then $\neg a\Rightarrow b$ is also true" holds, you can form the truth table:

$\begin{array}{ccccc}a&b&a\Rightarrow b&\neg a&\neg a\Rightarrow b\\1&1&1&0&1\\1&0&0&0&1\\0&1&1&1&1\\0&0&1&1&0\end{array}$

When the result of the column $a\Rightarrow b$ takes value 1 (true), the result of the column $\neg a\Rightarrow b$ is not always 1, then the statement is false.

7 0

2 years ago

Three different whole numbers add up to 31.

lubasha [3.4K]

Let's find the least possibilities:

First number: 6
Second number: 8
Third number: 10

6 + 8 + 10 = 24

Now we can see that we are still missing 31 - 24 = 7.

7 can be gained by adding 3 and 4, so:

First number: 6 + 3 = 9
Second number: 8 + 4 = 12
Third number: 10

9 + 12 + 10 = 31

5 0

2 years ago

Use implicit differentiation to find an equation of the tangent line to the curve at the given point. x2/3 + y2/3 = 4 (−3 3 , 1)

vovikov84 [41]

Answer with Step-by-step explanation:

We are given that an equation of curve

$x^{\frac{2}{3}}+y^{\frac{2}{3}}=4$

We have to find the equation of tangent line to the given curve at point $(-3\sqrt3,1)$

By using implicit differentiation, differentiate w.r.t x

$\frac{2}{3}x^{-\frac{1}{3}}+\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=0$

Using formula : $\frac{dx^n}{dx}=nx^{n-1}$

$\frac{2}{3}y^{-\frac{1}{3}}\frac{dy}{dx}=-\frac{2}{3}x^{-\frac{1}{3}}$

$\frac{dy}{dx}=\frac{-\frac{2}{3}x^{-\frac{1}{3}}}{\frac{2}{3}y^{-\frac{1}{3}}}$

$\frac{dy}{dx}=-\frac{x^{-\frac{1}{3}}}{y^{-\frac{1}{3}}}$

Substitute the value x= $-3\sqrt3,y=1$

Then, we get

$\frac{dy}{dx}=-\frac{(-3\sqrt3)^{-\frac{1}{3}}}{1}$

$\frac{dy}{dx}=-(-3^{\frac{3}{2}})^{-\frac{1}{3}}=-\frac{1}{-(3)^{\frac{3}{2}\times \frac{1}{3}}}=\frac{1}{\sqrt3}$

Slope of tangent=m= $\frac{1}{\sqrt3}$

Equation of tangent line with slope m and passing through the point $(x_1,y_1)$ is given by

$y-y_1=m(x-x_1)$

Substitute the values then we get

The equation of tangent line is given by

$y-1=\frac{1}{\sqrt3}(x+3\sqrt3)$

$y-1=\frac{x}{\sqrt3}+3$

$y=\frac{x}{\sqrt3}+3+1$

$y=\frac{x}{\sqrt3}+4$

This is required equation of tangent line to the given curve at given point.

8 0

3 years ago