Question

Given three consecutive integers, if the sum of the first and third integers is increased by 8, the result is 5 less than triple the second integer. Find the three consecutive integers. *

Answer 1

We are looking for the value of the second integer, so let's mark it as X.

Then three consecutive integers are : (x-1) , x , (x+1)

The sum of the first and the third integers (X-1) + (X+1)

Five less than three times the second integer 3X - 5

Now we can write an equation and solve it for X

 (X-1)+(X+1)= 3X - 5 simplifying left part

 2X = 3X -5 subtract 2X from both sides

0 = X-5

X=5

SO THREE CONSECUTIVE INTEGERS ARE 4, 5, 6

Answer 2

Answer:

The three consecutive integers are 12, 13 & 14

Explanation:

Let the three consecutive integers be x, x + 1, x + 2

According to the question,

If sum of the first and third integers is increased by 8, the result is 5 less than triple the second integer.

$\therefore$ x + x + 2 + 8 = (x + 1) × 3 - 5

2x + 10 = 3x + 3 - 5

2x + 10 = 3x - 2

10 + 2 = 3x - 2x

x = 12

So, The three consecutive integers are 12, 13 & 14