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ASHA 777 [7]
2 years ago
12

the human eye is able to detect as little as 2.35×10−18 j of green light of wavelength 510 nm. calculate the minimum number of p

hotons of green light that can be detected by the human eye.
SAT
1 answer:
Fantom [35]2 years ago
8 0

The minimum number of photons of green light that can be detected by the human eye is 6.

Given that;

E = nhc/λ

E = energy of the photon = 2.35 * 10^-18 J

n = number of photons = ?

h = Planks constant = 6.6 * 10^-34 Js

c = speed of light = 3 * 10^8 m/s

λ = 510 * 10^-9 m

Making number of photons the subject of the formula;

n =2.35 * 10^-18 *  510 * 10^-9 / 6.6 * 10^-34 * 3 * 10^8

n = 6 photons

Learn more: brainly.com/question/9260704

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Step-by-step explanation:

<u>Given</u> :

  • \small\red\bull Initial velocity (u) = 15 m/s
  • \small\red\bull Acceleration (a) = 3.0 m/s²
  • \small\red\bull Time = 4 seconds

<u>To</u><u> </u><u>Find</u> :

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<u>Using</u><u> </u><u>Formula</u> :

\longrightarrow{\pmb{\sf{v = u + at}}}

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  • \small\blue\star u = initial velocity
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Substituting the values in the formula to find the final velocity :

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\longrightarrow{\sf{v = 15 + (3.0 \times 4)}}

\longrightarrow{\sf{v = 15 + (3 \times 4)}}

\longrightarrow{\sf{v = 15 +(12)}}

\longrightarrow{\sf{v = 15 +12}}

\longrightarrow{\sf{v = 27 \:  {m/s}^{2}}}

\star{\underline{\boxed{\red{\sf{v = 27 \:  {m/s}^{2}}}}}}

Hence, the final speed of bicycle would be 27 m/s².

\rule{300}{1.5}

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