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ASHA 777 [7]
2 years ago
12

the human eye is able to detect as little as 2.35×10−18 j of green light of wavelength 510 nm. calculate the minimum number of p

hotons of green light that can be detected by the human eye.
SAT
1 answer:
Fantom [35]2 years ago
8 0

The minimum number of photons of green light that can be detected by the human eye is 6.

Given that;

E = nhc/λ

E = energy of the photon = 2.35 * 10^-18 J

n = number of photons = ?

h = Planks constant = 6.6 * 10^-34 Js

c = speed of light = 3 * 10^8 m/s

λ = 510 * 10^-9 m

Making number of photons the subject of the formula;

n =2.35 * 10^-18 *  510 * 10^-9 / 6.6 * 10^-34 * 3 * 10^8

n = 6 photons

Learn more: brainly.com/question/9260704

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Explanation:

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8 0
2 years ago
A client is 45 years old and has a resting heart rate of 75 bpm issa.
Firlakuza [10]

The target heart rate of the 45 year old client with a resting heart rate of 75 bpm is; 135 bpm

Complete question is;

A client is 45 years old and has a resting heart rate of 75 bpm using the karvonen formula what is their target heart rate at an exercise intensity of 60%.

We are given;

Age of client = 45 years

Resting Heart rate = 75 bpm

%Intensity = 60%

The karvonen formula is;

Target Heart Rate = [(max HR − resting HR) × %Intensity] + resting HR

Formula for maximum heart rate is;

Max HR = 220 - age

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Thus;

Target Heart rate = [(175 - 75) × 0.6] + 75

Target Heart rate = (100 × 0.6) + 75

Target Heart rate = 60 + 75

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Read more on target heart rate at; brainly.com/question/7593179

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