18. Describe the shape of the data distribution.

Is a=πd2 a area of a circle

kati45 [8]

A=r^2pi is the area of a circle

8 0

3 years ago

A triangle has side lengths of (8d – 3) centimeters, (6d + 2) centimeters, and

alisha [4.7K]

The perimeter of a triangle is the sum of its side lengths.

The perimeter of the triangle is: $14d + 7f +7$

The sides of the triangle are:

Side 1 = (8d - 3) cm

Side 2 = (6d + 2) cm

Side 3 = (7f + 8) cm

The perimeter (P) is calculated as:

P = Side 1 + Side 2 + Side 3

So, we have:

$P = (8d - 3) + (6d + 2) + (7f + 8)$

Remove brackets

$P = 8d - 3 + 6d + 2 + 7f + 8$

Collect like terms

$P = 8d + 6d + 7f - 3 + 2 + 8$

$P = 14d + 7f +7$

Hence, the perimeter of the triangle is: $14d + 7f +7$

Read more about perimeters at:

brainly.com/question/6465134

3 0

3 years ago

Help me pls and thank you

charle [14.2K]

Answer:

To make a table NOT a function you can make any input value lead to two or more outputs.

Step-by-step explanation:

Ex.

(2,3)

(1,4)

(6,7)

(2,8)

4 0

3 years ago

Which of the following describes the domain of the piecewise function g of x is equal to the piecewise function of the quantity

yuradex [85]

The domain of the function is given by (–∞, –3) ∪ (–3, 2) ∪ (2, ∞)

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The function is given by:

$g(x) = \frac{x^2 + 3x}{x^2 + x - 6}, x < 3$

$g(x) = \log_{2}{x + 5}, x \geq 3$

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For the second definition, the restriction is that x + 5 has to be positive. Since the definition is only valid for $x \geq 3$ , this will always be true.
In the second definition, the denominator cannot be zero, thus the zeros of the denominator will be outside the domain.

These zeros are found using Bhaskara, we have the quadratic function $x^2 + x - 6 = 0$ , thus the coefficients are $a = 1, b = 1, c = -6$ .

$\Delta = b^2 - 4ac = (1)^2 - 4(1)(-6) = 25$

$x_1 = \frac{-b + \sqrt{\Delta}}{2a} = \frac{-1 + 5}{2} = 2$

$x_2 = \frac{-b - \sqrt{\Delta}}{2a} = \frac{-1 - 5}{2} = -3$

Thus, x = 2 and x = -3 are outside the domain, which is given by:

(–∞, –3) ∪ (–3, 2) ∪ (2, ∞)

A similar problem is given at brainly.com/question/13136492

6 0

3 years ago

Find the domain and range of the relation, and determine whether it is a function. {(1, −1), (2, −2), (3, −3), (4, −4), (5, −5)}

tekilochka [14]

Answer:

All of the values that can go into a relation or function (input) are called the domain.

All of the values that come out of a relation or function (output) are called the range.

Range may also be referred to as "image".

Note that both relations and functions have domains and ranges.

The domain is the set of all first elements of ordered pairs (x-coordinates).

The range is the set of all second elements of ordered pairs (y-coordinates).

Only the elements "used" by the relation or function constitute the range.

definition

Domain: all x-values that are to be used (independent values).

Range: all y-values that are used (dependent values).

Set Builder notation may be used to express domains and ranges.

Step-by-step explanation:

All of the values that can go into a relation or function (input) are called the domain.

All of the values that come out of a relation or function (output) are called the range.

Range may also be referred to as "image".

Note that both relations and functions have domains and ranges.

The domain is the set of all first elements of ordered pairs (x-coordinates).

The range is the set of all second elements of ordered pairs (y-coordinates).

Only the elements "used" by the relation or function constitute the range.

definition

Domain: all x-values that are to be used (independent values).

Range: all y-values that are used (dependent values).

Set Builder notation may be used to exp-restate the appropriate domains for the functions shown below.

When functions are expressed as "rules" (formulas), be sure to think about possible "problem" spots before stating the domain. Remember that the domain is the x-values that are allowed by the function's equation. In most cases, a graph will help show the domain.

ss domains and ranges.

5 0

4 years ago