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3 years ago

Pls answer i need help asap lol, No links (30 points + brainly)

Mathematics

1 answer:

professor190 [17]3 years ago

7 0

The corresponding answers for each student plan are:

plan A: 15 years

plan B: 5 years

plan C: 10 years

plan D: 9 years

Thus, first, the graph corresponding to each of the plans must be analyzed. The Y-axis corresponds to money and the x-axis corresponds to the time in years.

Thus, in-plane A, it can be observed that to reach the desired value, the graph will be projected in exponential, so it will be close to 15 years. In plan B, this projection will be reached around 5 years. In plans C and D, this projection will be 10 years and 9 years respectively.

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3 years ago

The question is in the picture:

rosijanka [135]

Answer:

b) The measure of angle B is 117°.

Step-by-step explanation:

Angles A and C are vertical angles, so are congruent. Angles C and 27° total 90°, so ...

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Only choice B is correct.

8 0

4 years ago

What is the x And y intercept of (10,0) and (0,-10)

Radda [10]

The y-intercept is found by letting x = 0 and finding / calculating y. That would be (0, -10).

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4 0

3 years ago

a. Suppose we had $15,192 cash and invested it in the bank at 16 percent interest, how much would you have at the end of 1, 2, 3

Goryan [66]

Answer:

Part a) $\$17,622.72$

Part b) $\$20,442.36$

Part c) $\$23,713.13$

Part d) $\$27,507.23$

Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

A is the Final Investment Value

P is the Principal amount of money to be invested

r is the rate of interest in decimal

t is Number of Time Periods

n is the number of times interest is compounded per year

Part a) How much would you have at the end of 1 year?

in this problem we have

$t=1\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*1}=\$17,622.72$

Part b) How much would you have at the end of 2 year?

in this problem we have

$t=2\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*2}=\$20,442.36$

Part c) How much would you have at the end of 3 year?

in this problem we have

$t=3\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*3}=\$23,713.13$

Part d) How much would you have at the end of 4 year?

in this problem we have

$t=4\ years\\ P=\$15,192\\ r=0.16\\n=1$

substitute in the formula above

$A=15,192(1+\frac{0.16}{1})^{1*4}=\$27,507.23$

5 0

3 years ago