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gulaghasi [49]
3 years ago
9

Can someone please help me with this?

Mathematics
2 answers:
almond37 [142]3 years ago
7 0

Hello,

Ali is right, Khamis is wrong. Why because Khamis forgot to put the negative sign in front of 5b, it should be wrote -5b in the second line and not 5b.

And then Khamis should have divided -5b by -5b.

Good Luck

ololo11 [35]3 years ago
6 0
Ali is correct
Ali is correct
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How do you do distributive property to write equivalent expression for the perimeter of a triangle
Karolina [17]

Answer:

Look down

Step-by-step explanation:

So, to use distributive property you have to multiply the out side to the inside.

3(9-4)=15-8

Multiply 3and nine then 4.

3+27-12=15-8

I hope this helped you

6 0
3 years ago
Cos(x+y)/cosxcosy+tanxtany=1
adelina 88 [10]

Answer:

See explanation

Step-by-step explanation:

Use formula

\cos (x+y)=\cos x\cos y-\sin x\sin y

Substitute it into the first fraction:

\dfrac{\cos (x+y)}{\cos x\cos y}\\ \\=\dfrac{\cos x\cos y-\sin x\sin y}{\cos x\cos y}\\ \\=\dfrac{\cos x\cos y}{\cos x\cos y}-\dfrac{\sin x\sin y}{\cos x\cos y}\\ \\=1-\dfrac{\sin x}{\cos x}\cdot \dfrac{\sin y}{\cos y}\\ \\=1-\tan x\tany

Consider the whole expression:

\dfrac{\cos (x+y)}{\cos x\cos y}+\tan x\tan y\\ \\=1-\tan x \tan y+\tan x\tan y\\ \\=1

Done!

6 0
3 years ago
Which expression is equivalent to 5.4−1.8 ? A. −1.8+5.4 B.−1.8−5.4 C. 1.8 + 5.4 D.1.8−5.4
Digiron [165]
The correct answer is A: -1.8 + 5.4. Adding a negative is the same as subtracting. 
6 0
3 years ago
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In triangle △ABC, ∠ABC=90°, BH is an altitude. Find the missing lengths. AB=9, and AC=12, find HC.
pickupchik [31]

Answer:

Step-by-step explanation:

It is given that in △ABC, ∠ABC=90°, BH is an altitude and AB=9 and AC=12, thus using the Pythagoras theorem in △ABC, we get

(AC)^{2}=(AB)^{2}+(BC)^{2}

(12)^{2}=(9)^2+(BC)^2

144=81+(BC)^2

(BC)^2=63

BC=\sqrt{63}

Now, From ΔABC and ΔHBC, we have

∠ABC=∠BHC(each90)

∠ACB=∠HCB (Common)

By AA similarity, ΔABC is similar to ΔHBC.

Thus, using the similarity condition, we get

\frac{HC}{BC}=\frac{BC}{AC}

\frac{HC}{\sqrt{63}}=\frac{\sqrt{63}}{12}

HC=\frac{63}{12}=\frac{21}{4}

7 0
3 years ago
Find the product (8x+2)(7x+4)
noname [10]

Answer:

It's in the doc below

Step-by-step explanation:

Hope it helps

4 0
3 years ago
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