Answer:
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Answer:
y = 2x + 2
Step-by-step explanation:
<em>(a) Slope
</em>
The point-slope formula for a straight line is
y₂ - y₁ = m(x₂ - x₁)
The line goes through the points (-1, 0) and (0, 2).
2 – 0 = m[0 – (-1)]
2 = m
(b) y-intercept
y = mx + b
Use the point (0, 2)
2 = 2× 0+ b
2 = 0 + b
b = 2
∴ y = 2x + 2
Answer:
Ainsworth (1970) identified three main attachment styles, secure (type B), insecure avoidant (type A) and insecure ambivalent/resistant (type C).
Step-by-step explanation:
For example, Schaffer and Emerson suggested that attachments develop in four stages: asocial stage or pre-attachment (first few weeks), indiscriminate attachment (approximately 6 weeks to 7 months), specific attachment or discriminate attachment (approximately 7-9 months) and multiple attachment (approximately 10
Answer:
x = -2 , y = 4
Step-by-step explanation:
given:
5x + 2y = -2 <em>*4</em>
4x + 3y = 4 <em>*5</em>
Solving simultaneously,
20x + 8y = -8 ....eq 1
(-) 20x +15y = 20 ...eq 2
.............................................
-7y = -28
y = -28 / -7
y = 4
using equation 2,
20x +15(4) = 20
20x = -40
x = -2
Answer:
C. 666
Step-by-step explanation:
USING PEMDAS we can solve this problem.
