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Ne4ueva [31]
4 years ago
12

What is 60 divided by 5 +1 X(12-6)? ....(step by step)what to do

Mathematics
1 answer:
natita [175]4 years ago
5 0

Answer:

5.455

Step by step explanation

Going by BODMAS

Bracket=(12-6)=6

Multiplication =(1*6)=6

Addition=(5+6)=11

Therefore; 60/11=5.455

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Nita uses 1/3 of a carton of 12 eggs how many eggs does she use
Valentin [98]
What's 1/3 of 12?

Mulitply 1/3 times 12 = 4

Nita uses 4 eggs.
5 0
3 years ago
An engineer is going to redesign an ejection seat for an airplane. The seat was designed for pilots weighing between 150 lb and
lisov135 [29]

Answer:

(a) 0.50928

(b) 0.857685.

Step-by-step explanation:

We are given that an engineer is going to redesign an ejection seat for an airplane. The new population of pilots has normally distributed weights with a mean of 155 lb and a standard deviation of 29.2 lb i.e.;                                                         \mu = 160 lb  and \sigma = 27.5 lb

(A) We know that Z = \frac{X - \mu}{\sigma} ~ N(0,1)

Let X = randomly selected pilot  

If a pilot is randomly selected, the probability that his weight is between 150 lb and 201 lb = P(150 < X < 201)

P(150 < X < 201) = P(X < 201) - P(X <= 150)

P(X < 201) = P( \frac{X - \mu}{\sigma} < \frac{201 - 155}{29.2} ) = P(Z < 1.57) = 0.94179

P(X <= 150) = P( \frac{X - \mu}{\sigma}  < \frac{150 - 155}{29.2} ) = P(Z < -0.17) = 1 - P(Z < 0.17) = 1 - 0.56749

                                                                                                   = 0.43251

Therefore, P(150 < X < 201) = 0.94179 - 0.43251 = 0.50928 .

(B) We know that for sampling mean distribution;

           Z = \frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } } ~ N(0,1)

If 39 different pilots are randomly selected, the probability that their mean weight is between 150 lb and 201 lb is given by P(150 < X bar < 210);

 P(150 < X bar < 210) = P(X bar < 201) - P(X bar <= 150)

P(X bar < 201) = P( \frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } } < \frac{201 - 155}{\frac{29.2}{\sqrt{39} } } ) = P(Z < 9.84) = 1 - P(Z >= 9.84)

                                                                                  = 0.999995

P(X bar <= 150) = P( \frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } } < \frac{150 - 155}{\frac{29.2}{\sqrt{39} } } ) = P(Z < -1.07) = 1 - P(Z < 1.07)

                                                                                   = 1 - 0.85769 = 0.14231

Therefore,  P(150 < X bar < 210) = 0.999995 - 0.14231 = 0.857685.

C) If the tolerance level is very high to accommodate an individual pilot then it should be appropriate ton consider the large sample i.e. Part B probability is more relevant in that case.

3 0
3 years ago
If the second term of a geometric sequence of real numbers is -2 and the fifth term is 16 then what is the fourteenth term?
Agata [3.3K]
<h3>Given</h3>

A geometric sequence such that ...

a_2=-2\quad\text{and}\quad a_5=16

<h3>Find</h3>

a_{14}

<h3>Solution</h3>

We can use the ratio of the given terms to find the common ratio of the sequence, then use that to find the desired term from one of the given terms. We don't actually need the common ratio (-2). All we need is its cube (-8).

a_2=a_1r^{(2-1)}=a_1r^1\\a_5=a_1r^{(5-1)}=a_1r^4\\a_{14}=a_1r^{(14-1)}=a_1r^13=a_5r^9\\\\\dfrac{a_5}{a_2}=\dfrac{a_1r^4}{a_1r^1}=r^3=\dfrac{16}{-2}=-8\\\\r^9=\left(r^3\right)^3=(-8)^3=-512\\a_{14}=a_5(-512)\\\\a_{14}=-8192

7 0
3 years ago
A cylinder has a height of 11.1 yards and a diameter of 34.4 yards. What is its volume? Use a
GarryVolchara [31]

Answer:

Why? You have it there. Anyways, here's the step=by step.

Step-by-step explanation:

The equation for the volume of a cylinder is

V= π × height × radius²

or

V=π × r² × h

What you'll do then is multiply

11.1 × 34.4² × 3.14

Type that in a calculator and boom, you got your answer!

5 0
2 years ago
What is the reason for each step in the solution of the equation?
Alexxx [7]

as you can see you have to use commutative property given !!!!!!!!!


8 0
3 years ago
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