1. Take an arbitrary point that lies on the first line y=3x+10. Let x=0, then y=10 and point has coordinates (0,10).
2. Use formula 
to find the distance from point 
to the line Ax+By+C=0.
The second line has equation y=3x-20, that is 3x-y-20=0. By the previous formula the distance from the point (0,10) to the line 3x-y-20=0 is:
.
3. Since lines y=3x+10 and y=3x-20 are parallel, then the distance between these lines are the same as the distance from an arbitrary point from the first line to the second line.
Answer: 
.
Answer:
(-2,-3)=5
(0,3)=3
Step-by-step explanation:
(-2,-3)=
2+3
(0,3)=
0+3
Answer: 
Step-by-step explanation:
Since the center of dilation is not at the origin, we can use the following formula in order to find the coordinates of the vertices of the triangle D'E'F':
Where "O" is the center of dilation at (a,b) and "k" is the scale factor.
In this case you can identify that:
Therefore, susbtituting values into the formula shown above, you get that the coordinates ot the resulting triangle D'E'F, are the following:
Vertex D' → 
Vertex E' → 
Vertex F' → 
Answer:
This is a genuine statement of you look real closely at it.
I am joyous to assist you anytime.
