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Sergeeva-Olga [200]
3 years ago
13

Which value of m is a counterexample for the following statement?

Mathematics
2 answers:
Aleonysh [2.5K]3 years ago
8 0

Answer: 7

The prime numbers here are 3, 5, 7, and 11. This means that 9 is not prime. Since 7 +2 is 9, this disproves that m + 2 is also prime.

Would appreciate brainly <3

luda_lava [24]3 years ago
7 0

Answer:

true

Step-by-step explanation:

because you can start at zero and go on forever adding twos but it'll still be the same

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denis-greek [22]

TheThe  area of the shaded region  if the radius of the outer circle is 4 and the radius of the inner circle is 2 is 12π.

<h3>Area of the shaded region</h3>

Area of a circle = πr²

r =radius of the circle

Area of the outer circle:

Area of the outer circle = π(4)²

Area of the outer circle = 16π

Area of the inner circle:

Area of the inner circle = π (2)²

Area of the inner circle = 4 π

Area of the shaded Region :

Area of the shaded Region = 16π - 4 π

Area of the shaded Region = 12π

Therefore the  area of the shaded region  if the radius of the outer circle is 4 and the radius of the inner circle is 2 is 12π.

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1 year ago
Solve for x<br> 14x = 5(2x – 4) – 12
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3 years ago
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Angelina_Jolie [31]

Answer:

yes

Step-by-step explanation:

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3 years ago
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Triangle ABC is congruent to triangle DFE. Find x<br><br> 6<br><br> 12<br><br> 8<br><br> 4
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4 years ago
Find f such that f'(x) = 5x² + 9x - 7 and f(0) = 8.
faltersainse [42]

Answer:

\frac{5}{3}x^3+\frac{9}{2}x^2-7x+8\\

Step-by-step explanation:

Integrate your function with respect to x to get the non-differentiated form.

\int(5x^2+9x-7)dx=\frac{5}{3}x^3+\frac{9}{2}x^2-7x+c\\

Plug in your known value of x to get your value for your constant

f(0) = 8\\ \frac{5}{3}(0^3)+\frac{9}{2}(0^2)-7(0)+c = 8 \\c=8

This gives you your function to be

\frac{5}{3}x^3+\frac{9}{2}x^2-7x+8\\

6 0
3 years ago
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