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3 years ago

11

2miles less than 3333yards

1 answer:

Bess [88]3 years ago

4 0

To find out what 2 miles minus 3,333 yards is, first what you have to do is convert one unit to the other. I decided to convert 2 miles into yards. What you can do is multiple how ever many yards is one mile by two. So, there are 1,760 yards in 1 mile. 1,760 x 2 is 3,520. So now we have to subtract 3,520- 3,333.
The answer is 187.

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Solve the system. find x,y, and z please show all steps<br><br> x-y+z=1<br> x+y+3z=-3<br> 2x-y+2z=0

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Solving the system we get, x= -1, y= -2 and z= 0

Step-by-step explanation:

Solving the equations to find x, y and z

$x-y+z=1\,\,\,eq(1)\\x+y+3z=-3\,\,\,eq(2)\\2x-y+2z=0\,\,\,eq(3)$

Adding eq(1) and eq(2)

$x-y+z=1\\x+y+3z=-3\\--------\\2x+4z=-2\,\,\,\,eq(4)\\$

Adding eq(2) and eq(3)

$x+y+3z=-3\\2x-y+2z=0\\----------\\3x+5z=-3\,\,\,eq(5)$

Multiplying eq(4) by 3 and eq(5) by 2

$6x+12z=-6\\6x+10z=-6\\-\,\,\,-\,\,\,\,\,\,\,\,\,\,\,\,\,\,+\\----------\\2z=0\\z=0$

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Putting value of z in eq(4)

$2x+4z=-2\\2x+4(0)=-2\\2x=-2\\x=-1$

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Now putting value of z=0 and x =-1 in equation 1

$x-y+z=1\\-1-y+0=1\\-y=1+1\\-y=2\\y=-2$

So, value of y = -2

So, solving the system we get, x= -1, y= -2 and z= 0

Keywords: Solve the system

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kirill115 [55]

Hello!

Given the two points, $(x_{1}, y_{1})$ and $(x_{2}, y_{2})$ , and to find the distance between these two points is found by using the formula:

$d = \sqrt{(x_{2}-x_{1})^{2} + (y_{2}-y_{1})^{2}}$

$(x_{1}, y_{1})$ is assigned to one the points, in this case, is (4, 1).

$(x_{2}, y_{2})$ is assigned to other point, which is (9, 1).

Then, plug in these values into the formula and solve.

$d = \sqrt{(9-4)^{2}-(1-1)^{2}}$

$d = \sqrt{5^{2}-0^{2}}$

$d = \sqrt{25}$

$d = 5$

Therefore, the distance between the two points is 5.

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