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3 years ago

At Emily’s closet 1/3 of the cloths are white and 1/5 are black what. What fraction of Emilly’s clothes are black and white ?

Mathematics

2 answers:

Tcecarenko [31]3 years ago

8 0

Answer:

5/8

Step-by-step explanation:

vfiekz [6]3 years ago

3 0

8/15

Since 1/5 and 1/3 have different denominators, they cannot be added directly.
Multiply the denominators (5×3=15)
Multiply each with the other denominator 3×(1/5)=3/15, 5×(1/3)=5/15
Now, 3/15 +5/15=8/15

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Solutions of x^5-32i=0 in rectangular form.

elixir [45]

$\bf i^5\implies i^4i\implies 1i\implies i
\\\\\\
32=2^5\\\\
-------------------------------\\\\
x^5-32i=0\implies x^5=32i\implies x=\sqrt[5]{32i}\implies x=\sqrt[5]{2^5i^5}
\\\\\\
x=\sqrt[5]{(2i)^5}\implies x=2i\implies x=0+2i\implies (0~,~2)$

6 0

2 years ago

FInd the surface area of the triangular prism

Marta_Voda [28]

Answer:

273.7

Step-by-step explanation:

first fine the sides that isn't the base.

triangle area formula: (b*h)/2

(14*9)/2 = 63

since there are 3 sides you multiply this by three.

63*3=189

then find the base.

same formula since its a triangle.

(12.1*14)/2 = 84.7

now add them both up:

84.7+189 = 273.7

hope this helps!

3 0

3 years ago

Read 2 more answers

A student earned a grade of 80% on a math test that had20 problems. How many problems on this test did the student answer correc

Georgia [21]

Answer:

Only 16 problems correct

Step-by-step explanation:

Well I thought that since 80% is 4/5 then I should do 20 divided by 5 which will get me 4 and since I'm doing 4/5 I should go all the way up to 80% of 20 which will get me 16.

I'm not making that much sense but

Hope this helps :)

5 0

2 years ago

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modelled by the function C(t)=8(e

Alexxx [7]

Answer:

the maximum concentration of the antibiotic during the first 12 hours is 1.185 $\mu g/mL$ at t= 2 hours.

Step-by-step explanation:

We are given the following information:

After an antibiotic tablet is taken, the concentration of the antibiotic in the bloodstream is modeled by the function where the time t is measured in hours and C is measured in $\mu g/mL$

$C(t) = 8(e^{(-0.4t)}-e^{(-0.6t)})$

Thus, we are given the time interval [0,12] for t.

We can apply the first derivative test, to know the absolute maximum value because we have a closed interval for t.
The first derivative test focusing on a particular point. If the function switches or changes from increasing to decreasing at the point, then the function will achieve a highest value at that point.

First, we differentiate C(t) with respect to t, to get,

$\frac{d(C(t))}{dt} = 8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)})$

Equating the first derivative to zero, we get,

$\frac{d(C(t))}{dt} = 0\\\\8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0$

Solving, we get,

$8(-0.4e^{(-0.4t)}+ 0.6e^{(-0.6t)}) = 0\\\displaystyle\frac{e^{-0.4}}{e^{-0.6}} = \frac{0.6}{0.4}\\\\e^{0.2t} = 1.5\\\\t = \frac{ln(1.5)}{0.2}\\\\t \approx 2$