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Llana [10]
3 years ago
9

A term is a constant, variable, or multiplicative combination of the two.

Mathematics
2 answers:
Helga [31]3 years ago
8 0
I needed this thank you so much you saved my test
butalik [34]3 years ago
3 0

Answer:

there are four terms

Step-by-step explanation:

3x^2

2y

-4z

5

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(- 1, 2) and (9, - 3)
slava [35]

9/5

the distance is 9 over, and 5 up.

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Help geometry will give brainliest
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The distance from the owl to the squirrel would be found by using the law of sins/co-sins

Cos (known angle) = adjacent leg / hypotenuse ( distance wanted)

cos(50) = 14 / x

x = 14 / cos50

x = 21.78 feet

 The problem doesn't say if the answer should be rounded or not. You may have to round the answer if needed.



4 0
3 years ago
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Which ordered pair is in the solution set of the system of linear inequalities graphed below?
garik1379 [7]

Answer:

(1,-4)

Step-by-step explanation:

6 0
3 years ago
Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
maw [93]

Answer:

The number of individuals included in the summary is 146.

Step-by-step explanation:

The frequency distribution table provided is as follows:

Class Intervals    Frequency

    100 - 199               24

   200 - 299              90

   300 - 399              27

   400 - 499                1

   500 - 599               4

The lower class limit it the smallest value of each class interval.

Lower class limit = {100, 200, 300, 400, 500}

The upper class limit it the highest value of each class interval.

Upper class limit = {199, 299, 399, 499, 599}

The lower class boundaries are the lower class limits decreased by 0.5 and the upper class boundaries are the upper class limits increased by 0.5.

Class boundaries:

   99.5 - 199.5  

  199.5 - 299.5

  299.5 - 399.5

  399.5 - 499.5

  499.5 - 599.5

The class width is the difference between the class boundaries of each class.

Class width = 199.5 - 99.5 = 100

So, the class width is 100.

The midpoints of a class is the average value of the boundaries of a class.

\text{Midpoint}_{100-199}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{99.5+199.5}{2}\\\\=149.5

\text{Midpoint}_{200-299}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{199.5+299.5}{2}\\\\=249.5

\text{Midpoint}_{300-399}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{299.5+399.5}{2}\\\\=349.5

\text{Midpoint}_{400-499}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{399.5+499.5}{2}\\\\=449.5

\text{Midpoint}_{500-599}=\frac{\text{Lower class boundary} + \text{Upper class boundary}}{2}\\

                         =\frac{499.5+599.5}{2}\\\\=549.5

The number of individuals included in the summary is the sum of all frequencies.

\text{Number of Individuals}=24 + 90 + 27 + 1 + 4=146

Thus, the number of individuals included in the summary is 146.

3 0
3 years ago
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563-68= +(21x73)= ??????<br><br> also a pic of Ruka and Akur
frez [133]

Answer:

I think it is 2028 I am not a 100%

Step-by-step explanation:

8 0
3 years ago
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