First, "boxes of two sizes" means we can assign variables: Let x = number of large boxes y = number of small boxes "There are 115 boxes in all" means x + y = 115 [eq1] Now, the pounds for each kind of box is: (pounds per box)*(number of boxes) So, pounds for large boxes + pounds for small boxes = 4125 pounds "the truck is carrying a total of 4125 pounds in boxes" (50)*(x) + (25)*(y) = 4125 [eq2] It is important to find two equations so we can solve for two variables. Solve for one of the variables in eq1 then replace (substitute) the expression for that variable in eq2. Let's solve for x: x = 115 - y [from eq1] 50(115-y) + 25y = 4125 [from eq2] 5750 - 50y + 25y = 4125 [distribute] 5750 - 25y = 4125 -25y = -1625 y = 65 [divide both sides by (-25)] There are 65 small boxes. Put that value into either equation (now, which is easier?) to solve for x: x = 115 - y x = 115 - 65 x = 50 There are 50 large boxes.
Answer:
2.897
Step-by-step explanation:
Let us find the mean and variance for the sample first.
105 104 110 112
114 106 108 109
Mean = sum/8 = 108.5
Variance = 12
Std dev = sq rt of variance = 3.464
Std error = std dev/ sq rt n
since n =8, we get std error = 1.225
Since sample size is small, df =8-1 =7
For 95% confidence intervals, t critical value for two tailed=2.365
Margin of error = std error x t critical = 1.225(2.365)
=2.897
The answer is 36
lmk if you need steps
The function represented in the table is linear.
