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3 years ago

PLEASE ANSWER THIS ASAP THE ONES I GOT WRONG PLEASE TELL ME THE RIGHT ANSWER

Mathematics

2 answers:

Ksenya-84 [330]3 years ago

4 0

Yes it’s 1/3 and then tier 2 on the right.

schepotkina [342]3 years ago

3 0

Answer:

for line b - the slope is 0, not undefined. an undefined slope is a vertical line.

for line d - the slope is -1/3. slope is written rise over run, so just count the units that it goes down and how many it goes right. it goes down 1 and right 3, so it is -1/3.

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A line passes through the point (4,-6) and he a slope -3/4. Which is the equation of the line?

ANEK [815]

Answer:

The equation of the line is 3x + 4y + 12 = 0

Step-by-step explanation:

$given \: that \: the \: line \: passes \: through \: (4 , - 6) \\ and \: has \: the \: slope \: of \: \frac{ - 3}{4} \\ the \: equation \: of \: the \: line \: is \\ y - y1 = m(x - x1) \\ here \: x1 = 4 \: \: \: y1 = - 6 \: \: and \: m = \frac{ - 3}{4} \\ on \: substituting \: the \: values \: in \: formula \\ y - ( - 6) = \frac{ - 3}{4} (x - 4) \\ y + 6 = \frac{ - 3}{4} (x - 4) \\ 4(y + 6) = - 3(x - 4) \\ 4y + 24 = - 3x + 12 \\ 3x + 4y + 24 - 12 = 0 \\ 3x + 4y + 12 = 0$

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

8 0

3 years ago

If the point (2,-5) is reflected in the line y=x, then the image is what? { this is about reflections btw}

nikitadnepr [17]

In this question the answer is C

hope this helped

4 0

3 years ago

(2x/3)-(2x/5)=-60 and .2x+.9y=19.2

aleksandrvk [35]

Value of x=-225

Value of y=71.33

Explanation :

2x/3-2x/5=-60 (1)

0.2x+0.9y=19.2 (2)

(2x*5-2x*3)/(3*5)=-60

(10x-6x)/15=-60

4x/15=-60

4x=15*-60

4x=-900

x=-900/4=-225

consider (2)

0.2x+0.9y=19.2

substitute the value of x in (2)

0.2*-225+0.9y=19.2

0.9y=19.2+45=64.2

y=(64.2)/(0.9)=71.33

3 0

3 years ago

5/6 x 3/20 as a fraction

Fantom [35]

Answer:

1/8

Step-by-step explanation:

7 0

3 years ago

What is the midpoint of the segment?

Andre45 [30]

The midpoint of a segment $A(x_A;\ y_A);\ B(x_B;\ y_B)\\\\M_{AB}\left(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2}\right)$

A(-12;-3); B(3;-8)

$M_{AB}\left(\dfrac{-12+3}{2};\ \dfrac{-3+(-8)}{2}\right)\to M_{AB}\left(\dfrac{-9}{2};\ \dfrac{-11}{2}\right)\to M_{AB}(-4.5;-5.5)$

7 0

3 years ago