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laiz [17]
3 years ago
5

PLEASE ANSWER THIS ASAP THE ONES I GOT WRONG PLEASE TELL ME THE RIGHT ANSWER

Mathematics
2 answers:
Ksenya-84 [330]3 years ago
4 0
Yes it’s 1/3 and then tier 2 on the right.
schepotkina [342]3 years ago
3 0

Answer:

for line b - the slope is 0, not undefined. an undefined slope is a vertical line.

for line d - the slope is -1/3. slope is written rise over run, so just count the units that it goes down and how many it goes right. it goes down 1 and right 3, so it is -1/3.

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A line passes through the point (4,-6) and he a slope -3/4. Which is the equation of the line?
ANEK [815]

Answer:

The equation of the line is 3x + 4y + 12 = 0

Step-by-step explanation:

given \: that \: the \: line \: passes \: through \: (4 , - 6) \\ and \: has \: the \: slope \: of \:  \frac{ - 3}{4}  \\ the \: equation \: of \: the \: line \: is \\ y - y1 = m(x - x1) \\ here \: x1 = 4 \:  \:  \: y1 =  - 6 \:  \: and \: m =  \frac{ - 3}{4}  \\ on \: substituting \: the \: values \: in \: formula \\ y - ( - 6) =  \frac{ - 3}{4} (x - 4) \\ y + 6 = \frac{ - 3}{4} (x - 4)  \\ 4(y + 6) =  - 3(x - 4) \\ 4y + 24 =  - 3x + 12 \\ 3x + 4y + 24 - 12 = 0 \\ 3x + 4y + 12 = 0

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS</em><em> </em><em>FOR GIVING ME THE OPPORTUNITY TO</em><em> </em><em>ANSWER YOUR QUESTION</em><em>. </em>

8 0
3 years ago
If the point (2,-5) is reflected in the line y=x, then the image is what? { this is about reflections btw}
nikitadnepr [17]
In this question the answer is C

hope this helped
4 0
3 years ago
(2x/3)-(2x/5)=-60 and .2x+.9y=19.2
aleksandrvk [35]

Value of x=-225

Value of y=71.33

Explanation :

2x/3-2x/5=-60 (1)      

0.2x+0.9y=19.2    (2)    

(2x*5-2x*3)/(3*5)=-60  

   (10x-6x)/15=-60  

 4x/15=-60  

4x=15*-60

4x=-900

x=-900/4=-225    

consider (2)  

0.2x+0.9y=19.2    

substitute the value of x in (2)  

0.2*-225+0.9y=19.2  

0.9y=19.2+45=64.2

y=(64.2)/(0.9)=71.33

3 0
3 years ago
5/6 x 3/20 as a fraction
Fantom [35]

Answer:

1/8

Step-by-step explanation:

7 0
3 years ago
What is the midpoint of the segment?
Andre45 [30]
The midpoint of a segment A(x_A;\ y_A);\ B(x_B;\ y_B)\\\\M_{AB}\left(\dfrac{x_A+x_B}{2};\ \dfrac{y_A+y_B}{2}\right)

A(-12;-3); B(3;-8)

M_{AB}\left(\dfrac{-12+3}{2};\ \dfrac{-3+(-8)}{2}\right)\to M_{AB}\left(\dfrac{-9}{2};\ \dfrac{-11}{2}\right)\to M_{AB}(-4.5;-5.5)
7 0
3 years ago
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