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Natalka [10]
2 years ago
9

No spaces in your answer boxes.

Mathematics
1 answer:
Alborosie2 years ago
4 0

Answer:

Number of Cents = 10x

Step-by-step explanation:

Since w

Since we know that there are 10 cents in a dime, the amount of cents in an unknown quantity of dimes is 10 * the number of dimes.

Therefore the number of cents in x dimes is 10x

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If y=x+2 we’re changed to y=x-1 how would the graph of a new function compare with the first one
butalik [34]

The y-intercept is being changed. In the equations given we are using the formula (y=mx +b), b means the y intercept. In this we are changing the y intercept from 2 to -1. There is nothing else being changed.

6 0
3 years ago
X^2+6x+8÷x^2-16 simplify
Misha Larkins [42]

Answer:

The answer is in the file below, I wasn't able to make it in text form.

6 0
2 years ago
What are the first three terms of the Arithmetic Sequence an=11-3(n-1)?
svlad2 [7]

Answer:

11,8,5

Step-by-step explanation:

an=11-3(n-1)

Let n=1

a1 = 11 - 3(1-1)

    = 11 -0

    =11

Let n=2

a2 = 11-3(2-1)

     = 11 -3(1)

     = 8

Let n=3

a3 = 11-3(3-1)

    = 11 -3(2)

    = 11 -6

    =5

5 0
3 years ago
A piggy bank contains $5.60 in nickels and dimes. The number of nickels is 8 less than 3 times the dimes. How many nickels and d
Musya8 [376]
The value of the coin times the number of coins all added up equals the total value of the piggy bank
so
0.05n + 0.10d = 5.60

then they have given us "number of nickels is 8 less than 3 times the dimes"
this translates to
n = 3d - 8

we plug this into our first equation and we get
0.05(3d - 8) + 0.10d = 5.60

now we solve for d
first we can distribute the 0.05
0.15d - 0.40 + 0.10d = 5.60

then we can add the 0.15d and 0.10d together
and get
0.25d - 0.40 = 5.60

then we can add 0.40 to both sides
0.25d = 6.00

then divide both sides by 0.25
d = 6.00 / 0.25 = 24
so we have 24 dimes


then to find nickels, we plug in 24 for d into
n = 3d - 8
and get
n = 3(24) - 8
n = 72 - 8
n = 64

therefore we have
64 nickels
and
24 dimes
4 0
3 years ago
Read 2 more answers
A Find the amount compounded annually on Rs 25,000 for 2 years if the rates of
STatiana [176]

Answer:

Amount = Rs. 30250 when Rate = 10%

<em>Amount = Rs. 31360 when Rate = 12%</em>

Step-by-step explanation:

Given

Principal, P = Rs.\ 25,000

Time, t = 2\ years

Rate; R_1 = 10\%

Rate; R_2 = 12\%

Number of times (n) = Annually

n = 1

Required

Determine the Amount for both Rates

Amount (A) is calculated by:

A = P(1 + \frac{r}{n})^{nt}

When Rate = 10%, we have:

Substitute 25,000 for P; 2 for t; 1 for n and 10% for r

A = 25000 * (1 + \frac{10\%}{1})^{1 * 2}

A = 25000 * (1 + \frac{10\%}{1})^{2}

A = 25000 * (1 + 10\%)^{2}

Convert 10% to decimal

A = 25000 * (1 + 0.10)^{2}

A = 25000 * (1.10)^{2}

A = 25000 * 1.21

A = 30250

Hence;

<em>Amount = Rs. 30250 when Rate = 10%</em>

When Rate = 12%, we have:

Substitute 25,000 for P; 2 for t; 1 for n and 10% for r

A = 25000 * (1 + \frac{12\%}{1})^{1 * 2}

A = 25000 * (1 + \frac{12\%}{1})^{2}

A = 25000 * (1 + 12\%)^{2}

Convert 12% to decimal

A = 25000 * (1 + 0.12)^{2}

A = 25000 * (1.12)^{2}

A = 25000 * 1.2544

A = 31360

Hence;

<em>Amount = Rs. 31360 when Rate = 12%</em>

7 0
3 years ago
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