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2 years ago

Convert 244 16 to decimal:

Mathematics

2 answers:

xz_007 [3.2K]2 years ago

7 0

Answer:

I know it’s already been answered but I got 15.25

Step-by-step explanation:

vlabodo [156]2 years ago

4 0

Answer:

15.25 is your answer

Step-by-step explanation:

You might be interested in

Arrange the digits 1-9 in the 9 boxes to make three equivalent fractions,all equal to 1/2

ElenaW [278]

I'm confused because there are no boxes, but maybe 2/4 3/6 5/10

4 0

3 years ago

Whats the difference in 2/3 - 1/6

nasty-shy [4]

Answer:

2/3&1/6

2/3- 1/6

the LCM for 3 and 6 is 6

=(2x6)/(3x6) -(1x6)/(6x6)

=4/6-1/6

=(4-1)/6

find the difference

= 3/6

=1/2

2/3-1/6= 1/2

By using LCM method, 1/2 is the equivalent fraction by subtracting 1/6 from 2/3.

2/3&1/6

2/3- 1/6

cross multiply

2x6-1x3/3x6

simplify

12-3/18

=9/18

= 1/2

2/3-1/6 = 1/2

By using cross multiplication method, 1/2 is the difference between two fractions 2/3 and 1/6.

Step-by-step explanation:

hope that helps>3

7 0

3 years ago

What are the focus and directrix of the parabola that is the graph of the function f(x)=x²?

Hitman42 [59]

Answer:

Step-by-step explanation:

Given

$y=x^2$

comparing it with standard equation $x^2=4ay$

so 4a=1

$a=\frac{1}{4}$

so Focus of parabola is (0,0)

directrix

y=-a

here $a=\frac{1}{4}$

$y=-\frac{1}{4}$

5 0

3 years ago

At noon, ship A is 130 km west of ship B. Ship A is sailing east at 25 km/h and ship B is sailing north at 20 km/h. How fast is

Hitman42 [59]

Answer:

answer = 12.87 km/h

Step-by-step explanation:

Given

Ship A is sailing east at 25 km/h = $\frac{dx}{dt}$

ship B is sailing north at 20 km/h = $\frac{dy}{dt}$

here x and y are the sailing at t = 4 : 00 pm for ship A and B respectively

so we get x = 4 ×25 =100 km/h

y = 4× 20 = 80 km/h

let z is the distance between the ships, we need to find $\frac{dz}{dt}$ at t = 4 hr

At noon, ship A is 130 km west of ship B (12:00 pm)

so equation will be

$z^2 = (130-x)^2 + y^2......................(i)\\put x = 100 and y = 80 \\\\we | | get \\$

$z^2 = 30^2 + 80^2\\z =\sqrt{7300} km/h$

derivative first equation w . r. to t we get

$2z\frac{dz}{dt} =$ $-2(130-x)\frac{dx}{dt}$ $+2y\frac{dy}{dt}$

$\frac{dz}{dt} =\frac{1}{z}[(x -130)\frac{dx}{dt} +y\frac{dy}{dt}]$

$\frac{dz}{dt} = \frac{( -20\times25 + 80\times20)}{\sqrt{7300} }$

$= \frac{1100}{85.44}\\ = 12.87km/h$

8 0

3 years ago

If you can explain your answer that’d be great!! Thank you!

Rasek [7]

Answer:

$A(t)=A_{0}e^{\frac{ln(\frac{1}{2})}{22}t}$

Step-by-step explanation:

This half life exponential decay equation goes by the formula:

$A(t)=A_{0}e^{kt}$

Where

$k=\frac{ln(\frac{1}{2})}{Half-Life}$

Since half life is given as 22, we plug that into "Half-Life" in the formula for k and then plug in the formula for k into the exponential decay formula:

So,

$k=\frac{ln(\frac{1}{2})}{Half-Life}\\k=\frac{ln(\frac{1}{2})}{22}$

Now

$A(t)=A_{0}e^{\frac{ln(\frac{1}{2})}{22}t}$

third choice is correct.

8 0

3 years ago