Two cars leave towns 760 kilometers apart at the same time and travel toward each other. One car's rate is 12 kilometers per hou
r less than the other's. If they meet in 4 hours, what is the rate of the slower car
1 answer:
Answer:
89 km/hr
Step-by-step explanation:
Distance = Rate(speed) × Time
D = R × T
T = 4 hours
One car's rate is 12 kilometers per hour less than the other's.
Hence:
First's car's rate = r × 4 = 4r
Second car's distance = (r + 12) × 4 = 4r + 48
4r + 4r + 48 = 760
8r + 48 = 760
8r = 760 - 48
8r = 712
r = 712/8
r = 89 km/hr
The rate of the slower car is 89 km/hr
You might be interested in
Answer:
since you recorded the first marble then replaced it, you drew 10 blue marbles, so therefore we can predict the next marble you drew, was blue.
Step-by-step explanation:
Answer:
6 days
Step-by-step explanation:
Answer:
width=3
then length=5×3
now,
Area=l×b
= 15×3
=45
3/2+3/2=3 That is a good equation because all of the characters are bigger than one 3/2 is equal to 1.5 and 3 is greater than 1
Ralphs is 7.5x+10
frank’s is 10x
