Question

Two cars leave towns 760 kilometers apart at the same time and travel toward each other. One car's rate is 12 kilometers per hour less than the other's. If they meet in 4 hours, what is the rate of the slower car

Answer 1

Answer:

89 km/hr

Step-by-step explanation:

Distance = Rate(speed) × Time

D = R × T

T = 4 hours

One car's rate is 12 kilometers per hour less than the other's.

Hence:

First's car's rate = r × 4 = 4r

Second car's distance = (r + 12) × 4 = 4r + 48

4r + 4r + 48 = 760

8r + 48 = 760

8r = 760 - 48

8r = 712

r = 712/8

r = 89 km/hr

The rate of the slower car is 89 km/hr