Two cars leave towns 760 kilometers apart at the same time and travel toward each other. One car's rate is 12 kilometers per hou
r less than the other's. If they meet in 4 hours, what is the rate of the slower car
1 answer:
Answer:
89 km/hr
Step-by-step explanation:
Distance = Rate(speed) × Time
D = R × T
T = 4 hours
One car's rate is 12 kilometers per hour less than the other's.
Hence:
First's car's rate = r × 4 = 4r
Second car's distance = (r + 12) × 4 = 4r + 48
4r + 4r + 48 = 760
8r + 48 = 760
8r = 760 - 48
8r = 712
r = 712/8
r = 89 km/hr
The rate of the slower car is 89 km/hr
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