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2 years ago

If x = 5-2√6, find the value of:(i) x + 1/x(ii) x² + 1/x²Please solve ASAP

Mathematics

1 answer:

Vitek1552 [10]2 years ago

5 0

Answer:

x+(1/x) = 10 and
x²+ (1/x²) = 98

Step-by-step explanation:

Given that :

x = 5-2√6

1/x = 1/(5-2√6)

The denominator = 5-2√6

The Rationalising factor of 5-2√6 = 5+2√6

On Rationalising the denominator then

⇛ 1/x = [1/(5-2√6)]×[(5+2√6)/5+2√6)]

⇛ 1/x = (5+2√6)/[5-2√6)(5+2√6)]

⇛ 1/x = (5+2√6)/[5²-(2√6)²]

Since (a+b)(a-b) = a²-b²

Where ,

a = 5 and
b = 2√6

⇛1/x = (5+2√6)/(25-24)

⇛ 1/x = (5+2√6)/1

⇛ 1/x = 5+2√6

Now,

x +(1/x)

⇛ 5-2√6+5+2√6

⇛ 5+5

⇛ 10

Therefore, x+(1/x) = 10.

On squaring both sides then

⇛ [x+(1/x)]² = 10²

⇛ x²+2(x)(1/x)+(1/x)² =100

⇛ x²+2+(1/x)² = 100

⇛ x²+(1/x²) = 100-2

⇛ x²+(1/x²) = 98

Therefore, x²+(1/x²) = 98.

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The senior class at a very small high school has 25 students. Officers need to be elected for four positions: President, Vice-Pr

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Answer:

(a) The total number of ways to select 4 officers from from 25 students is 12,650.

(b) The total number of ways the four officers are selected such that the President and Treasurer are girls and the Vice-President and Secretary are boys is 5,148.

Step-by-step explanation:

(a)

It is provided that there are a total of n = 25 students.

Officers need to be elected for four positions:

President, Vice-President, Secretary, and Treasurer.

k = 4

In mathematics, the procedure to select k items from n distinct items, without replacement, is known as combinations.

The formula to compute the combinations of k items from n is given by the formula:

${n\choose k}=\frac{n!}{k!(n-k)!}$

Compute the number of ways to select 4 students from from 25 as follows:

${25\choose 4}=\frac{25!}{4!(25-4)!}$

$=\frac{25!}{4!\times 21!}\\\\=\frac{25\times 24\times 23\times 22\times 21!}{4!\times 21!}\\\\=\frac{25\times 24\times 23\times 22}{4\times 3\times 2\times 1}\\\\=12650$

Thus, the total number of ways to select 4 officers from from 25 students is 12,650.

(b)

It is provided that of the 25 students, there are 13 girls and 12 boys in the class.

For the post of President and Treasurer only girls are selected.

For the post of Vice-President and Secretary only boys are selected.

Compute the number of ways to select 2 girls for the post of President and Treasurer as follows:

${13\choose 2}=\frac{13!}{2!(13-2)!}$

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${12\choose 2}=\frac{12!}{2!(12-2)!}$

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The number of ways the four officers are selected such that the President and Treasurer are girls and the Vice-President and Secretary are boys is:

${13\choose 2}\times {12\choose 2}=78\times 66=5148$

Thus, the total number of ways the four officers are selected such that the President and Treasurer are girls and the Vice-President and Secretary are boys is 5,148.

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If x = 5-2√6, find the value of:(i) x + 1/x(ii) x² + 1/x²Please solve ASAP​

If x = 5-2√6, find the value of:(i) x + 1/x(ii) x² + 1/x²Please solve ASAP