9.68 X 10^3. Hope this helped :)
Given the question "six people went into the woods to look for truffles. On average they collected 7 truffles per person. The average of the last four people to come back was 8 truffles per person. In fact the fourth person to come backk had 11 treuffles in is basket. How many truffles did the last three people collect altogether?"
Since the average truffles collected by the six people is 7, then the total truffles collected by the six people is 6 x 7 = 42 truffles.
Since the last four people that came back collected an average of 8 truffles, then the total number of truffles collected by the last four people that came back is 4 x 8 = 32 truffles.
Given that the fourth person collected 11 truffles, therefore, <span>the last three people collected a total of 32 - 11 = 21 truffles.</span>
Answer:
Step-by-step explanation:
Two ∆s can be considered to be congruent to each other using the Side-Angle-Side Congruence Theorem, if an included angle, and two sides of a ∆ are congruent to an included angle and two corresponding sides of another ∆.
∆ABC and ∆DEF has been drawn as shown in the attachment below.
We are given that 
and also 
.
In order to prove that ∆ABC 
∆DEF using the Side-Angle-Side Congruence Theorem, an included angle which lies between two known side must be made know in each given ∆s, which must be congruent accordingly to each other.
The included angle has been shown in the ∆s drawn in the diagram attached below.
Therefore, the additional information that would be need is:
Answer:
d=62
Step-by-step explanation:
180-56=124
2d=124
Divide both sides by 2
d=62
Answer:
See below.
Step-by-step explanation:
I will assume that 3n is the last term.
First let n = k, then:
Sum ( k terms) = 7k^2 + 3k
Now, the sum of k+1 terms = 7k^2 + 3k + (k+1) th term
= 7k^2 + 3k + 14(k + 1) - 4
= 7k^2 + 17k + 10
Now 7(k + 1)^2 = 7k^2 +14 k + 7 so
7k^2 + 17k + 10
= 7(k + 1)^2 + 3k + 3
= 7(k + 1)^2 + 3(k + 1)
Which is the formula for the Sum of k terms with the k replaced by k + 1.
Therefore we can say if the sum formula is true for k terms then it is also true for (k + 1) terms.
But the formula is true for 1 term because 7(1)^2 + 3(1) = 10 .
So it must also be true for all subsequent( 2,3 etc) terms.
This completes the proof.
