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3 years ago

What is 2,000/3.67 estimate

Mathematics

1 answer:

RideAnS [48]3 years ago

6 0

Answer:

an estimate would be 2000/4 so it would be 500

Step-by-step explanation:

hope this helped <3

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Simplify the expression.

Alja [10]

Answer:

-2r^3+4r^2+12r-4

Step-by-step explanation:

6r^3-2r^2+12r-4-8r^3+6r^2

(6r^3-8r^3)+(-2r^2+6r^2)+12r-4

simplify

-2r^3+4r^3+12r-4

4 0

4 years ago

Find the first partial derivatives of the function f(x,y,z)=4xsin(y−z)

Amanda [17]

Answer:

$f_x(x,y,z)=4\sin (y-z)$

$f_x(x,y,z)=4x\cos (y-z)$

$f_z(x,y,z)=-4x\cos (y-z)$

Step-by-step explanation:

The given function is

$f(x,y,z)=4x\sin (y-z)$

We need to find first partial derivatives of the function.

Differentiate partially w.r.t. x and y, z are constants.

$f_x(x,y,z)=4(1)\sin (y-z)$

$f_x(x,y,z)=4\sin (y-z)$

Differentiate partially w.r.t. y and x, z are constants.

$f_y(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial y}(y-z)$

$f_y(x,y,z)=4x\cos (y-z)$

Differentiate partially w.r.t. z and x, y are constants.

$f_z(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial z}(y-z)$

$f_z(x,y,z)=4x\cos (y-z)(-1)$

$f_z(x,y,z)=-4x\cos (y-z)$

Therefore, the first partial derivatives of the function are $f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z)$ .

4 0

4 years ago

Which of the following is true when constructing a line graph?

Marat540 [252]

Answer:

Step-by-step explanation:

3 0

3 years ago

How do you get answer for the equation y-3.7=4.2

xz_007 [3.2K]

All you need to do is add 3.7 to the other side and since you don't need to divide anything from y, whatever you get will be your final answer. :)

5 0

4 years ago

Read 2 more answers

What is the square root of y^3

tia_tia [17]

Answer:

$y^{\frac{3}{2}$

Step-by-step explanation:

Let $m=\sqrt{y^3}$

$m=(y^3)^{\frac{1}{2}}\\\\m=y^{3\times \frac{1}{2}}\ \ \ \ \ \ \ \ \ [as\ (x^a)^b=x^{ab}]\\\\m=y^{\frac{3}{2}$

7 0

3 years ago