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ki77a [65]
3 years ago
5

Find the first partial derivatives of the function f(x,y,z)=4xsin(y−z)

Mathematics
1 answer:
Amanda [17]3 years ago
4 0

Answer:

f_x(x,y,z)=4\sin (y-z)

f_x(x,y,z)=4x\cos (y-z)

f_z(x,y,z)=-4x\cos (y-z)

Step-by-step explanation:

The given function is

f(x,y,z)=4x\sin (y-z)

We need to find first partial derivatives of the function.

Differentiate partially w.r.t. x and y, z are constants.

f_x(x,y,z)=4(1)\sin (y-z)

f_x(x,y,z)=4\sin (y-z)

Differentiate partially w.r.t. y and x, z are constants.

f_y(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial y}(y-z)

f_y(x,y,z)=4x\cos (y-z)

Differentiate partially w.r.t. z and x, y are constants.

f_z(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial z}(y-z)

f_z(x,y,z)=4x\cos (y-z)(-1)

f_z(x,y,z)=-4x\cos (y-z)

Therefore, the first partial derivatives of the function are f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z).

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