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2 years ago

Find x if 2^x=8^3x-8

Mathematics

1 answer:

Anon25 [30]2 years ago

5 0

Step-by-step explanation:

First we have to same the bases.

As we know 8=2^3.

Replace 8 with 2^3.

Like this .

2^3x=2^3(2x+1).

Now 3x=3(2x+1) distribute 3 by the Barker.

3x=6x+3.

6x+3=3x.

6x-3x=-3.

3x=-3.

X=-1.

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60 + 108 = 180<br> What property would this be

kvv77 [185]

Answer:

Non-intelligent

Step-by-step explanation:

It is wrong so who ever solved this equation is non-intelligent

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2 years ago

Evaluate the six trigonometric functions of the angle 0.

Arturiano [62]

Given:

Right triangle

To find:

The six trigonometric functions of θ

Solution:

Hypotenuse = 18

Adjacent side to θ = 10

Opposite side to θ = ?

Using Pythagoras theorem:

$\text {Hypotenuse}^2 = \text{adjacent}^2+\text{opposite}^2$

$18^2 =10^2+\text{opposite}^2$

$324=100+\text{opposite}^2$

Subtract 100 from both sides.

$224=\text{opposite}^2$

Taking square root on both sides.

$4\sqrt{14}=\text{opposite}$

Using trigonometric ratio formula:

$$\sin\theta =\frac{\text{opposite }}{\text{hypotenuse}}$

$$\sin\theta =\frac{4\sqrt{14} }{18}$

$$\csc\theta =\frac{\text{hypotenuse}}{\text{opposite }}$

$$\csc\theta =\frac{18}{4\sqrt{14} }$

$$\cos \theta=\frac{\text { adjacent side }}{\text { hypotenuse }}$

$$\cos \theta=\frac{10}{18}$

$$\sec \theta=\frac{\text { hypotenuse }}{\text { adjacent side }}$

$$\sec \theta=\frac{18 }{10}$

$$\tan \theta=\frac{\text { opposite side }}{\text { adjacent side }}$

$$\tan \theta=\frac{4\sqrt{14} }{10}$

$$\cot \theta=\frac{\text { adjacent side }}{\text { opposite side }}$

$$\cot \theta=\frac{10}{4\sqrt{14} }$

8 0

3 years ago

The distance between two cities on a map is 10 in. The actual distance between the cities is 135. What is the scale on the map?

spayn [35]

The scale on the map is 1 in = 13.5 units

135/10 = 13.5

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3 years ago

Which are perfect squares? Check all that apply.

den301095 [7]

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3 years ago

Read 2 more answers

I need help please I will mark you brainlists

V125BC [204]

Answer:

2. ΔABC is isosceles

Step-by-step explanation:

Given : m∠A = 50

m∠BCD = 180 - (m∠BDC + m∠DBC)

= 180 - (100 + 30)

= 50

then

m∠A = m∠BCD

therefore ΔABC is isosceles

6 0

2 years ago