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2 years ago

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Paisley drove to his new college and then came back home. His round trip was 212 miles. Paisley drives a Honda and gets 35 miles

for every gallon of gas. If Paisley needs to make 12 round trips, how much will it cost him in gas? Assuming the price of gas stays at $3.60.

1 answer:

san4es73 [151]2 years ago

7 0

Answer:

because of this the awnser

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Write and solve the equation for the following situation:

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Answer:

B.) x + (x + 16) = 90

2x+16=90

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x=74/2

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2 years ago

Which polynomial represents the difference below? (8x^2+9)-(6x^2+2x+2)

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Answer:

The polynomial is 2 x² - 2x + 7

Step-by-step explanation:

Given polynomial

(8 x² + 9 ) - (6x² +2x +2)

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= 8x² - 6x² - 2x + 9-2

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3 years ago

At an airport, 76% of recent flights have arrived on time. A sample of 11 flights is studied. Find the probability that no more

I am Lyosha [343]

Answer:

The probability is $P( X \le 4 ) = 0.0054$

Step-by-step explanation:

From the question we are told that

The percentage that are on time is p = 0.76

The sample size is n = 11

Generally the percentage that are not on time is

$q = 1- p$

$q = 1- 0.76$

$q = 0.24$

The probability that no more than 4 of them were on time is mathematically represented as

$P( X \le 4 ) = P(1 ) + P(2) + P(3) + P(4)$

=> $P( X \le 4 ) = \left n } \atop {}} \right.C_1 p^{1} q^{n- 1} + \left n } \atop {}} \right.C_2p^{2} q^{n- 2} + \left n } \atop {}} \right.C_3 p^{3} q^{n- 3} + \left n } \atop {}} \right.C_4 p^{4} q^{n- 4}$

$P( X \le 4 ) = \left 11 } \atop {}} \right.C_1 p^{1} q^{11- 1} + \left 11 } \atop {}} \right.C_2p^{2} q^{11- 2} + \left 11 } \atop {}} \right.C_3 p^{3} q^{11- 3} + \left 11 } \atop {}} \right.C_4 p^{4} q^{11- 4}$

$P( X \le 4 ) = \left 11 } \atop {}} \right.C_1 p^{1} q^{10} + \left 11 } \atop {}} \right.C_2p^{2} q^{9} + \left 11 } \atop {}} \right.C_3 p^{3} q^{8} + \left 11 } \atop {}} \right.C_4 p^{4} q^{7}$

$= \frac{11! }{ 10! 1!} (0.76)^{1} (0.24)^{10} + \frac{11!}{9! 2!} (0.76)^2 (0.24)^{9} + \frac{11!}{8! 3!} (0.76)^{3} (0.24)^{8} + \frac{11!}{7!4!} (0.76)^{4} (0.24)^{7}$

$P( X \le 4 ) = 0.0054$

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3 years ago

Does somebody knows how to do this problem?

pshichka [43]

Answer:

Angle Q is 51°

Angle R is 96°

(x=5 and the exterior angle is 84°)

Step-by-step explanation:

Exterior Angle Theorem says that angle that's outside the triangle (extend a side and see the angle between the side extension and the side) IS Equal to the sum of the two angles that are farther away.

17x - 1 = 33 + 10x + 1

Get all the x's on one side of the equation.

17x-10x - 1 = 33 + 10x-10x+1

7x - 1 = 33 + 1

7x - 1 = 34 add 1 to both sides

7x = 35 divide by 7

7x/7 = 35/7

x = 5

Not finished ! Find Angle Q

10x+1 = 10(5)+1= 51°

Angle PRQ is insidethe triangle. All the angles of a triangle add up to 180°

33° + 51° + R = 180°

84° + R = 180°

R = 96°

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2 years ago