All categories

3 years ago

Does anyone know the answer to this? thank you!

Mathematics

1 answer:

svetoff [14.1K]3 years ago

5 0

Answer:

$\alpha = \frac{arc \: length}{radius} \\ arc \: length = \alpha \times radius \\ = 50 \times \frac{\pi}{180} \times 7 \\ arc \: length = 350 \times \frac{\pi}{180} \\ = 1.94 \times \pi \\ = 6.1metre \\ thank \: you$

You might be interested in

9. The water level is 3 feet below your dock. The tide goes out, and the water level lowers 1 foot. A storm surge comes in, and

guapka [62]

We know that that the water level is 3 feet below your deck. (-3)
When the tide goes out, the water level lowers 1 foot. (-1)
A storm surge comes in, the water level rises 2 feet. (+2)

New water level: -3-1+2= -4+2= -2
The new water level is 2 feet below the dock.

Mark as brainliest pls. Any concern or comment, talk to me.

3 0

3 years ago

Read 2 more answers

A tunnel is built in form of a parabola. The width at the base of tunnel is 7 m. On

anastassius [24]

Given:

The width at the base of parabolic tunnel is 7 m.

The ceiling 3 m from each end of the base there are light fixtures.

The height to light fixtures is 4 m.

To find:

Whether it is possible a trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel.

Solution:

The width at the base of tunnel is 7 m.

Let the graph of the parabola intersect the x-axis at x=0 and x=7. It means x and (x-7) are the factors of the height function.

The function of height is:

$h(x)=ax(x-7)$ ...(i)

Where, a is a constant.

The ceiling 3 m from each end of the base there are light fixtures and the height to light fixtures is 4 m. It means the graph of height function passes through the point (3,4).

Putting x=3 and h(x)=4 in (i), we get

$4=a(3)((3)-7)$

$4=a(3)(-4)$

$\dfrac{4}{(3)(-4)}=a$

$-\dfrac{1}{3}=a$

Putting $a=-\dfrac{1}{3}$ , we get

$h(x)=-\dfrac{1}{3}x(x-7)$ ...(ii)

The center of the parabola is the midpoint of 0 and 7, i.e., 3.

The width of the truck is 4 m. If is passes through the center then the truck must m 2 m on the left side of the center and 2 m on the right side of the center.

2 m on the left side of the center is x=1.5.

A trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is possible if h(1.5) is greater than 2.8.

Putting x=1.5 in (ii), we get

$h(1.5)=-\dfrac{1}{3}(1.5)(1.5-7)$

$h(1.5)=-(0.5)(-5.5)$

$h(1.5)=2.75$

It is clear that h(1.5)<2.8, therefore the trailer truck carrying cars is 4 m wide and 2.8 m high is going to drive through the tunnel is not possible.