Answer:
(A)12-19
Step-by-step explanation:
To construct a frequency distribution, we follow the steps below.
1. Find the largest and smallest values.
91 and 12 respectively
Compute the Range = Maximum - Minimum=91-12=79
2. Determine the number of classes desired.
In this case, we desire 10 classes
3. Next, we find the class width by dividing the range by the number of classes and rounding up.
79÷10 = 7.9
Rounded Up, Class Width=8
4. Pick a suitable starting point less than or equal to the minimum value.
Since our minimum value is 12, we pick a class starting with 12 and give a class width of 8.
Therefore the upper and lower limits of the first class is given as:
12-19.
Answer:
A
Step-by-step explanation:
SO right off the bat it cannot be c, for they do definatly change.
Next, lets find out how much they change by.
The median would now be 120. Since adding 1 more number would make it just 120. Instead of it being 120+130/2.
This is a decrease of 5. Because we can just subtract normal number by new number: 125-120=5.
Now, the mean is already 500/4. This equals 125.
So lets add 0 to that. So now we must divide it by 1 more number, 4+1=5.
That is 500/5. This equals 100.
This is a decrease of 25. Because we can again subtrasct the normal number by the new number: 125-100=25
That is 5x more of a decrease than the mean.
SO it must be A, since the mean decreased more than the median.
Answer:
2,3
Step-by-step explanation:
Let the first number be x
Hence, its next consecutive integer = x+1
By Factorizing the expression on the LHS. we get it equal to :-
Hence, we get two solutions for x, x=2, x= -3/5
As x is an integer, x=2 is the most suitable solution in this case.
Hence,
The numbers are 2,3
Answer:
7300
Step-by-step explanation:
