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Basile [38]
2 years ago
11

Use the Pythagorean theorem to find the length of the diagonal of a square that has

Mathematics
1 answer:
worty [1.4K]2 years ago
3 0

Answer:

How far (nearest foot) will it be from home plate to second base, assuming he builds it to that specification? ... A square lot has an area of 1,200 square meters. .... Therefore, we can use the Pythagorean Theorem to solve for the diagonal:.

Step-by-step explanation:

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Write an equation that could be used to find how many miles a hybrid suv can travel in the city on 20 gallons
vagabundo [1.1K]

Answer:

m=36×20

Step-by-step explanation:

A hybrid SUV uses 36 miles per gallon in the city.

The equation that could be used to find how many miles a hybrid SUV can travel in the city on 20 gallons of gas is m=36×20.

8 0
2 years ago
Use appropriate algebra and Theorem 7.2.1 to find the given inverse Laplace transform. (Write your answer as a function of t.)
Licemer1 [7]

Expand the expression as

(<em>s</em> + 1)³/<em>s</em> ⁵ = (<em>s</em> ³ + 3<em>s</em> ² + 3<em>s</em> + 1)/<em>s</em> ⁵

… = 1/<em>s</em> ² + 3/<em>s</em> ³ + 3/<em>s</em> ⁴ + 1/<em>s</em> ⁵

Then taking the inverse transform, you get

LT⁻¹ [1/<em>s</em> ² + 3/<em>s</em> ³ + 3/<em>s</em> ⁴ + 1/<em>s</em> ⁵]

… = LT⁻¹ [1/<em>s</em> ²] + LT⁻¹ [3/<em>s</em> ³] + LT⁻¹ [3/<em>s</em> ⁴] + LT⁻¹ [1/<em>s</em> ⁵]

… = LT⁻¹ [1!/<em>s</em> ²] + 3/2 LT⁻¹ [2!/<em>s</em> ³] + 1/2 LT⁻¹ [3!/<em>s</em> ⁴] + 1/24 LT⁻¹ [4!/<em>s</em> ⁵]

… = <em>t</em> + 3/2 <em>t</em> ² + 1/2 <em>t</em> ³ + 1/24 <em>t</em> ⁴

8 0
2 years ago
3( x - 2 ) + 2 (4x - 1)
Vika [28.1K]

Answer:

11x-8

Step-by-step explanation:

First distribute the 3 and 2. (Only in the parenthesis!):

3(x-2)+2(4x-1)

3x-6+8x-2

Combine like terms:

3x+8x=11x

-6-2=-8

So the answer is:

11x-8

4 0
2 years ago
A company employs two shifts of workers. Each shift produces a type of gasket where the thickness is the critical dimension. The
Oksanka [162]

Answer:

a) [-0.134,0.034]

b) We are uncertain

c) It will change significantly

Step-by-step explanation:

a) Since the variances are unknown, we use the t-test with 95% confidence interval, that is the significance level = 1-0.05 = 0.025.

Since we assume that the variances are equal, we use the pooled variance given as

s_p^2 = \frac{ (n_1 -1)s_1^2 + (n_2-1)s_2^2}{n_1+n_2-2},

where n_1 = 40, n_2 = 30, s_1 = 0.16, s_2 = 0.19.

The mean difference \mu_1 - \mu_2 = 10.85 - 10.90 = -0.05.

The confidence interval is

(\mu_1 - \mu_2) \pm t_{n_1+n_2-2,\alpha/2} \sqrt{\frac{s_p^2}{n_1} + \frac{s_p^2}{n_2}} = (-0.05) \pm t_{68,0.025} \sqrt{\frac{0.03}{40} + \frac{0.03}{30}}

= -0.05\pm 1.995 \times 0.042 = -0.05 \pm 0.084 = [-0.134,0.034]

b) With 95% confidence, we can say that it is possible that the gaskets from shift 2 are, on average, wider than the gaskets from shift 1, because the mean difference extends to the negative interval or that the gaskets from shift 1 are wider, because the confidence interval extends to the positive interval.

c) Increasing the sample sizes results in a smaller margin of error, which gives us a narrower confidence interval, thus giving us a good idea of what the true mean difference is.

6 0
3 years ago
A)2a+ 1=2a+3
Montano1993 [528]

Answer:

I'm not sure but at least i tried

8 0
3 years ago
Read 2 more answers
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