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3 years ago

Solve -3(x-2)=2(x-7) and write a reason for each step

Mathematics

2 answers:

seraphim [82]3 years ago

8 0

Answer:

4=x

Step-by-step explanation:

-3(x-2)=2(x-7)

Distribute -3 and 2.

-3x+6=2x-14

Add 3x to both sides of the equation.

6=5x-14

Add 14 to both sides of the equation.

20=5x

Divide 5 from both sides of the equation.

4=x

Hope this helps :)

madreJ [45]3 years ago

7 0

Answer:

x=5

Step-by-step explanation:

Our equation is

-3(x-2)=2(x-7)

First we will distribute -3 and 2, because in math when we have a number being multiplied into parenthesis we multiply both things inside of it

Our equation is now

-3x+6=2x-14

Next we subtract 6 from both sides because we want x to be on only one side

-3x=2x-20

Next we subtract 2x from both sides because we want x to equal something exactly

-5x=-20

Now we divide -5 from both sides because we only want x

x=5

Brainliest please :)

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After a picnic, 5/12 of the cornbread is left over. Val eats 4/5 of the leftover cornbread. What fraction of the cornbread does

Kay [80]

Answer:

5/12 - 4/5 = -23/60. You can't simplify -23/60. Hope this is right

Step-by-step explanation:

4/5= 48/60

5/12 = 25/60

25/60-48/60= -23/60

3 0

3 years ago

Whats the volume of the cylinder? Round your answer to the nearest hundred the top is B the left side of the cylinder is 13cm th

Wittaler [7]

Answer:

The volume of the cylinder is 163.3 m³.

Step-by-step explanation:

Given that,

Height = 13 cm

Base = 4 cm

So, radius = 2 cm

We need to calculate the volume of the cylinder

Using formula of cylinder

$V=\pi r^2h$

Where, r = radius

h = height

Put the value into the formula

$V=\pi\times(2)^2\times13$

$V=163.3\ cm^3$

Hence, The volume of the cylinder is 163.3 cm³.

6 0

3 years ago

what is the polynomial function of lowest degree with leading coefficient of 1 and roots 2 and 1 + square root2

Marta_Voda [28]

If the roots to such a polynomial are 2 and $1+\sqrt2$ , then we can write it as

$(x-2)(x-(1+\sqrt2))$

courtesy of the fundamental theorem of algebra. Now expanding yields

$(x-2)(x-1-\sqrt2)=x^2-2x-(1+\sqrt2)x+2(1+\sqrt2)=x^2-(3+\sqrt2)x+2+2\sqrt2$

which would be the correct answer, but clearly this option is not listed. Which is silly, because none of the offered solutions are *the* polynomial of lowest degree and leading coefficient 1.

So this makes me think you're expected to increase the multiplicity of one of the given roots, or you're expected to pull another root out of thin air. Judging by the choices, I think it's the latter, and that you're somehow supposed to know to use $1-\sqrt2$ as a root. In this case, that would make our polynomial

$(x-2)(x-(1+\sqrt2))(x-(1-\sqrt2))=x^3-4x^2+3x+2$

so that the answer is (probably) the third choice.

Whoever originally wrote this question should reevaluate their word choice...

5 0

3 years ago

If the coordinates of the endpoints of a diameter of the circle are known, the equation of a circle can be found. First, find

Evgesh-ka [11]

Answer:

The equation of the circle is $(x+3)^2+(y-5)^2 = 17$

Step-by-step explanation:

The complete question is

If the coordinates of the endpoints of a diameter of the circle are known, the equation of a circle can be found. First, find the midpoint of the diameter, which is the center of the circle. Then find the radius, which is the distance from the center to either endpoint of the diameter. Finally use the center-radius form to find the equation.

Find the center-radius form of the circle having the points (1,4) and (-7,6) as the endpoints of a diameter.

Consider that, if both points are the endpoints of a diameter, the center of the circle is the point that is exactly in the middle of the two points (that is, the point whose distance to each point is equal). Given points (a,b) and (c,d), by using the distance formula, you can check that the middle point is the average of the coordinates. Hence, the center of the circle is given by

$(\frac{1-7}{2}, \frac{4+6}{2}) = (-3,5)$ .

We will find the radius. Recall that the radius of the circle is the distance from one point of the circle to the center. Recall that the distance between points (a,b) and (c,d) is given by $\sqrt[]{(a-c)^2+(b-d)^2}$ . So, let us use (1,4) to calculate the radius.