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Gelneren [198K]
4 years ago
9

the length of a rectangle is 3 cm longer than it’d width. if the perimeter of the rectangle is 38, find it’s area.

Mathematics
1 answer:
lora16 [44]4 years ago
7 0

Answer:

88 cm²

Step-by-step explanation:

w = x

l = x + 3

P = 38

We know that P=2l+2w, so we substitute known values:

P=2l+2w\\38=2(x+3)+{2(x)}\\38=2x+6+2x\\38=4x+6\\32=4x\\8=x

Therefore, we know that the width (x) is 8 cm and the length (x + 3) is 8 + 3 = 11 cm. To verify, we can check that the perimeter equals 38:

8 + 11 + 8 + 11 = 38. <em>Check.</em>

Thus, the area of the rectangle is:

A=l\times{w}\\A=11\times{8}\\A=88

Therefore, the area is 88 cm².

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Answer:

x = 4

Explanation:

Given the expression;

\sqrt[]{x}-4\text{ = -2}

Add 4 to both sides

\begin{gathered} \sqrt[]{x}-4+4\text{ = -2+4} \\ \sqrt[]{x}=\text{ 2} \end{gathered}

Square both sides

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Hence the value of x is 4

undefined

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3 years ago
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vladimir2022 [97]

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Step-by-step explanation:

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iogann1982 [59]

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