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3 years ago

I have a problem with question 35

Mathematics

1 answer:

sveta [45]3 years ago

7 0

4/5k + 7/10 = 13/15k - 3/5
4/5k - 13/15k = -3/5 - 7/10
12/15k - 13/15k = -6/10 - 7/10
-1/15k = - 13/10
k = -13/10 * - 15/1
k = 195/10 = 39/2 or 19.5

or this way
4/5k + 7/10 = 13/15k - 3/5....multiply everything by LCD of 30
24k + 21 = 26k - 18
24k - 26k = -18 - 21
-2k = - 39
k = 39/2 or 19.5

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3 years ago

Graph a triangle (STU) and reflect it over the y-axis to create triangle ST'U'.

lukranit [14]

The x-coordinates of $\triangle S'T'U'$ will be the negation of the x-coordinates of $\triangle STU$

The line segment from S to the y-axis equals the line segment from S' to the y-axis. Similarly, the line segment from T to the y-axis equals the line segment from T' to the y-axis

See attachment for $\triangle STU$ and $\triangle S'T'U'$

In order to solve this question, I will make the following assumptions.

Assume that the coordinates of $\triangle STU$ are

$S = (4,5)$

$T = (5,9)$

$U=(3,8)$

Refer to attachment for illustrations

(1) Reflect $\triangle STU$ over y-axis and describe the transformation

To reflect $\triangle STU$ across the y-axis, the following rule must be followed

$(x,y) \to (-x,y)$

This means that:

$S = (4,5) \to S' = (-4,5)$

$T = (5,9) \to T' = (-5,9)$

$U=(3,8) \to U'=(-3,8)$

The description of the transformation is as follows:

Notice that the signs of the x-coordinates $\triangle STU$ and $\triangle S'T'U'$ of both triangles are different.

In other words, if the x-coordinate of one is positive, then the other will have a negative x-coordinate; and vice versa.

(2) Compare the segments and the line of reflection

To reflect across the y-axis means that the reflecting line is the y-axis, itself.

The distance between a point to the y-axis is the absolute value of the x-coordinate.

So, the distance between S and the y-axis is:

$S = |4| = 4$

The distance between S' and the y-axis is:

$S' = |-4| = 4$

We can conclude that the two line segments are equal.

This is the same for other point T and T' because of the formula used above.

From T and T' to the y-axis is:

$T =|5| =5$

$T' =|-5| =5$

Read more at:

brainly.com/question/938117

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3 years ago

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ASHA 777 [7]

Answer:

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I will use V=πr2h

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Hope this helped

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3 years ago

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VladimirAG [237]

Answer:

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BigorU [14]

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